NJSLA Algebra II The Real Number System. Practice it free.

Extend the properties of exponents to rational exponents and use properties of radicals and integer exponents. This Algebra II reporting domain maps to 5 practice skills and 8 representative questions from the playable bank.

Algebra IIN-RN5 mapped skills
What the test measures

The Real Number System skills

  1. N.RN.A.1-2 Rational exponents and radicals

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Try it now

8 free questions · 0/0 correct

Practice playmedium

Which expression is equivalent to 28+63+7\sqrt{28}+\sqrt{63}+\sqrt{7}?

28=27\sqrt{28}=2\sqrt{7}, 63=37\sqrt{63}=3\sqrt{7}, and 7=7\sqrt{7}=\sqrt{7}. Adding gives 27+37+7=672\sqrt{7}+3\sqrt{7}+\sqrt{7}=6\sqrt{7}.

Practice playeasy

If x\Large x and y\Large y are positive, which expression is equivalent to x10y8\Large \sqrt{x^{10} y^8}?

A square root divides each exponent by 2\Large 2: x102y82=x5y4\Large x^{\tfrac{10}{2}} y^{\tfrac{8}{2}} = x^5 y^4.

Practice playmedium

The impact speed, in feet per second, of an object dropped from a height can be estimated by multiplying the height, in feet, by 6464 and then taking the square root of the product. According to this method, what is the estimated impact speed, in feet per second, of an object dropped from a height of 1212 feet?

The product is 1264=76812 \cdot 64 = 768. Factor 768=2563768 = 256 \cdot 3, where 256256 is the largest perfect-square factor. So 768=2563=163\sqrt{768} = \sqrt{256 \cdot 3} = 16\sqrt{3}, and 33 is square-free.

Practice playeasy

Simplify: 161/216^{1/2}.

161/2=16=416^{1/2} = \sqrt{16} = 4.

Practice playmedium

Which expression is equivalent to 9800\sqrt{9800}?

9800=70229800 = 70^2 \cdot 2, so 9800=702\sqrt{9800} = 70\sqrt{2}.

Practice playeasy

Which expression is equivalent to 72+98\sqrt{72}+\sqrt{98}?

72=362=62\sqrt{72}=\sqrt{36 \cdot 2}=6\sqrt{2} and 98=492=72\sqrt{98}=\sqrt{49 \cdot 2}=7\sqrt{2}. Adding like radical terms gives 62+72=1326\sqrt{2}+7\sqrt{2}=13\sqrt{2}.

Practice playmedium

If p\Large p and q\Large q are positive, which expression is equivalent to p18q126\Large \sqrt[6]{p^{18} q^{12}}?

Divide each exponent by 6\Large 6: p186q126=p3q2\Large p^{\tfrac{18}{6}} q^{\tfrac{12}{6}} = p^3 q^2.

Practice playmedium

The diagonal length, in inches, of a certain square television screen can be estimated by multiplying the screen's area, in square inches, by 22 and then taking the square root of the product. According to this method, what is the estimated diagonal length, in inches, of a screen with an area of 216216 square inches?

The product is 2162=432216 \cdot 2 = 432. Factor 432=1443432 = 144 \cdot 3, where 144144 is the largest perfect-square factor. So 432=1443=123\sqrt{432} = \sqrt{144 \cdot 3} = 12\sqrt{3}, and 33 is square-free.

Keep practicing

Turn the real number system into game time.

The NJSLA placement starts with this test's real coverage map and finds the right difficulty.