Grade 10 · Geometry & measurement

Equation of a circle practice

Equation of a circle is a grade 10 math skill aligned to Common Core standard HSG.GPE.A.1: derive the equation of a circle of given center and radius using the Pythagorean Theorem; complete the square to find the center and radius of a circle given by an equation. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 30 equation of a circle problems our math games drill.

CCSS HSG.GPE.A.130 questions in the bank
Sample questions

Try 8 for free

Question 1easy

What is the radius of (x3)2+(y+1)2=16(x - 3)^{2} + (y + 1)^{2} = 16?

r2=16r^{2} = 16, so r=4r = 4.

Question 2easy

A circle has equation (x+8)2+(y3)2=49(x + 8)^{2} + (y - 3)^{2} = 49. What is the xx-coordinate of its center?

(x+8)2=(x(8))2(x + 8)^{2} = (x - (-8))^{2}, so the center's xx-coordinate is 8-8.

Question 3easy

What is the yy-coordinate of the center of the circle (x+1)2+(y7)2=4(x + 1)^{2} + (y - 7)^{2} = 4?

(y7)2(y - 7)^{2} means k=7k = 7; the center is (1,7)(-1, 7).

Question 4easy

What is the diameter of the circle (x2)2+(y7)2=36(x - 2)^{2} + (y - 7)^{2} = 36?

r=36=6r = \sqrt{36} = 6, so the diameter is 2r=122r = 12.

Question 5easy

For the circle (x1)2+(y4)2=81(x - 1)^{2} + (y - 4)^{2} = 81, what is the value of r2r^{2}?

In standard form the right-hand side equals r2r^{2}, so r2=81r^{2} = 81.

Question 6easy

What is the radius of the circle (x3)2+(y+2)2=25(x - 3)^{2} + (y + 2)^{2} = 25?

The right-hand side is r2=25r^{2} = 25, so r=25=5r = \sqrt{25} = 5.

Question 7easy

A circle is centered at the origin and passes through the point (6,8)(6, 8). What is its radius?

The radius is the distance from (0,0)(0, 0) to (6,8)(6, 8): 36+64=100=10\sqrt{36 + 64} = \sqrt{100} = 10.

Question 8easy

The graph of the equation (x7)2+(y3)2=25(x - 7)^{2} + (y - 3)^{2} = 25 is a circle in the coordinate plane. The point (a,b)(a, b) lies on the circle. Which of the following is a possible value for aa?

The center is (7,3)(7, 3) and the radius is 55. A point on the circle must satisfy a75|a - 7| \le 5, so 2a122 \le a \le 12. The value 99 is in this interval.

Drill it inside a game.

The free placement test finds your level, then every match serves equation of a circle questions at exactly the right difficulty.