Trig identities. Game on.

Trig identities is a grade 12 math skill aligned to Common Core standard HSF.TF.C.8: prove the Pythagorean identity sin²(θ) + cos²(θ) = 1 and use it to find sin(θ), cos(θ), or tan(θ) given one of them and the quadrant of the angle. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 20 trig identities problems our math games drill.

CCSS HSF.TF.C.820 questions in the bank
Kickoff

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Warm-upeasy

Which identity equals cos(2θ)?\cos(2\theta)\textsf{?}

One form of the double-angle identity is cos(2θ)=cos2θsin2θ.\cos(2\theta) = \cos^{2}\theta - \sin^{2}\theta\textsf{.}

Mid-gameeasy

Which is the Pythagorean identity?

The fundamental Pythagorean identity is sin2θ+cos2θ=1.\sin^{2}\theta + \cos^{2}\theta = 1\textsf{.}

Mid-gameeasy

If sinθ=35\sin\theta = \dfrac{3}{5} and cosθ=45,\cos\theta = \dfrac{4}{5}\textsf{,} what is tanθ?\tan\theta\textsf{?}

tanθ=sinθcosθ=3/54/5=34.\tan\theta = \dfrac{\sin\theta}{\cos\theta} = \dfrac{3/5}{4/5} = \dfrac{3}{4}\textsf{.}

Mid-gameeasy

If cosθ=23,\cos\theta = \dfrac{2}{3}\textsf{,} what is secθ?\sec\theta\textsf{?}

secθ=1cosθ=12/3=32.\sec\theta = \dfrac{1}{\cos\theta} = \dfrac{1}{2/3} = \dfrac{3}{2}\textsf{.}

Mid-gameeasy

If sinθ=513\sin\theta = \dfrac{5}{13} and cosθ=1213,\cos\theta = \dfrac{12}{13}\textsf{,} what is sin(2θ)?\sin(2\theta)\textsf{?}

sin(2θ)=2sinθcosθ=25131213=120169.\sin(2\theta) = 2\sin\theta\cos\theta = 2 \cdot \dfrac{5}{13} \cdot \dfrac{12}{13} = \dfrac{120}{169}\textsf{.}

Mid-gameeasy

Which identity equals 1+tan2θ?1 + \tan^{2}\theta\textsf{?}

The Pythagorean identity is 1+tan2θ=sec2θ.1 + \tan^{2}\theta = \sec^{2}\theta\textsf{.}

Mid-gameeasy

If sinθ=513\sin\theta = -\dfrac{5}{13} and cosθ=1213,\cos\theta = \dfrac{12}{13}\textsf{,} what is tanθ?\tan\theta\textsf{?}

tanθ=sinθcosθ=5/1312/13=512.\tan\theta = \dfrac{\sin\theta}{\cos\theta} = \dfrac{-5/13}{12/13} = -\dfrac{5}{12}\textsf{.}

Buzzer beatereasy

If cosθ=47,\cos\theta = -\dfrac{4}{7}\textsf{,} what is secθ?\sec\theta\textsf{?}

secθ=1cosθ=14/7=74.\sec\theta = \dfrac{1}{\cos\theta} = \dfrac{1}{-4/7} = -\dfrac{7}{4}\textsf{.}

Overtime

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