Grade 6 · Geometry & measurement

Area formulas (triangle, parallelogram, trapezoid) practice

Area formulas (triangle, parallelogram, trapezoid) is a grade 6 math skill aligned to Common Core standard 6.G.A.1: find the area of triangles, special quadrilaterals, and polygons by composing into rectangles or decomposing into triangles and other shapes. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 70 area formulas (triangle, parallelogram, trapezoid) problems our math games drill.

CCSS 6.G.A.170 questions in the bank
Sample questions

Try 8 for free

Question 1easy

Find the area of a parallelogram with base b=4b = 4 and height h=6h = 6.

Parallelogram area =b⋅h=4⋅6=24= b \cdot h = 4 \cdot 6 = 24.

Question 2easy

Find the area of a trapezoid with bases b1=5b_1 = 5 and b2=6b_2 = 6 and height h=4h = 4.

Trapezoid area =12(b1+b2)⋅h=12(5+6)⋅4=12(11)⋅4=22= \dfrac{1}{2}(b_1 + b_2) \cdot h = \dfrac{1}{2}(5 + 6) \cdot 4 = \dfrac{1}{2}(11) \cdot 4 = 22.

Question 3easy

Find the area of a triangle with base b=8b = 8 and height h=9h = 9.

Triangle area =12⋅b⋅h=12⋅8⋅9=36= \dfrac{1}{2} \cdot b \cdot h = \dfrac{1}{2} \cdot 8 \cdot 9 = 36.

Question 4easy

Find the area of a parallelogram with base b=2b = 2 and height h=9h = 9.

Parallelogram area =b⋅h=2⋅9=18= b \cdot h = 2 \cdot 9 = 18.

Question 5easy

Find the area of a trapezoid with bases b1=7b_1 = 7 and b2=10b_2 = 10 and height h=6h = 6.

Trapezoid area =12(b1+b2)⋅h=12(7+10)⋅6=12(17)⋅6=51= \dfrac{1}{2}(b_1 + b_2) \cdot h = \dfrac{1}{2}(7 + 10) \cdot 6 = \dfrac{1}{2}(17) \cdot 6 = 51.

Question 6easy

Find the area of a triangle with base b=4b = 4 and height h=8h = 8.

Triangle area =12⋅b⋅h=12⋅4⋅8=16= \dfrac{1}{2} \cdot b \cdot h = \dfrac{1}{2} \cdot 4 \cdot 8 = 16.

Question 7easy

Find the area of a parallelogram with base b=5b = 5 and height h=10h = 10.

Parallelogram area =b⋅h=5⋅10=50= b \cdot h = 5 \cdot 10 = 50.

Question 8easy

Find the area of a trapezoid with bases b1=6b_1 = 6 and b2=10b_2 = 10 and height h=7h = 7.

Trapezoid area =12(b1+b2)⋅h=12(6+10)⋅7=12(16)⋅7=56= \dfrac{1}{2}(b_1 + b_2) \cdot h = \dfrac{1}{2}(6 + 10) \cdot 7 = \dfrac{1}{2}(16) \cdot 7 = 56.

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Tests that cover area formulas (triangle, parallelogram, trapezoid):
SBACPSAT 8/9SATVTCAPSC READY
More Grade 6 skills:
Absolute valueCustom unit conversionsExponents notationMean change from data set editsDecimal operationsFraction-decimal-percent conversionMeasures of center and variabilityOrder of operationsAll Grade 6 practice →

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