Linear equation from two points (SAT). Game on.

Linear equation from two points (SAT) is a grade 9 math skill aligned to Common Core standard HSA.CED.A.2: create equations in two or more variables to represent relationships between quantities; graph equations on coordinate axes with labels and scales. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 linear equation from two points (sat) problems our math games drill.

CCSS HSA.CED.A.210 questions in the bank
Kickoff

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Warm-upeasy

A line passes through the points (0,−3)(0, -3) and (4,1)(4, 1). Which equation represents this line in slope-intercept form?

The slope is m=1−(−3)4−0=1m = \dfrac{1 - (-3)}{4 - 0} = 1. Because the line passes through (0,−3)(0, -3), the yy-intercept is b=−3b = -3 where x=0x = 0. The equation is y=x−3y = x - 3.

Mid-gamemedium

A line passes through the points (1,−4)(1, -4) and (5,4)(5, 4). Which equation represents this line in slope-intercept form?

The slope is m=4−(−4)5−1=2m = \dfrac{4 - (-4)}{5 - 1} = 2. Substitute (1,−4)(1, -4): −4=2(1)+b-4 = 2(1) + b, so b=−6b = -6. The equation is y=2x−6y = 2x - 6.

Mid-gamemedium

A line passes through the points (−1,4)(-1, 4) and (2,−2)(2, -2). Which equation represents this line in slope-intercept form?

The slope is m=−2−42−(−1)=−2m = \dfrac{-2 - 4}{2 - (-1)} = -2. Substitute (−1,4)(-1, 4): 4=−2(−1)+b4 = -2(-1) + b, so b=2b = 2. The equation is y=−2x+2y = -2x + 2.

Mid-gamemedium

A line passes through the points (2,1)(2, 1) and (6,4)(6, 4). Which equation represents this line in slope-intercept form?

The slope is m=4−16−2=34m = \dfrac{4 - 1}{6 - 2} = \dfrac{3}{4}. Substitute (2,1)(2, 1): 1=34(2)+b1 = \dfrac{3}{4}(2) + b, so b=−12b = -\dfrac{1}{2}. The equation is y=34x−12y = \dfrac{3}{4}x - \dfrac{1}{2}.

Mid-gamemedium

A line passes through the points (−3,0)(-3, 0) and (1,4)(1, 4). Which equation represents this line in slope-intercept form?

The slope is m=4−01−(−3)=1m = \dfrac{4 - 0}{1 - (-3)} = 1. Substitute (−3,0)(-3, 0): 0=1(−3)+b0 = 1(-3) + b, so b=3b = 3. The equation is y=x+3y = x + 3.

Mid-gamemedium

A line passes through the points (1,2)(1, 2) and (7,5)(7, 5). Which equation represents this line in slope-intercept form?

The slope is m=5−27−1=12m = \dfrac{5 - 2}{7 - 1} = \dfrac{1}{2}. Substitute (1,2)(1, 2): 2=12(1)+b2 = \dfrac{1}{2}(1) + b, so b=32b = \dfrac{3}{2}. The equation is y=12x+32y = \dfrac{1}{2}x + \dfrac{3}{2}.

Mid-gamemedium

A line passes through the points (−4,−1)(-4, -1) and (2,5)(2, 5). Which equation represents this line in slope-intercept form?

The slope is m=5−(−1)2−(−4)=1m = \dfrac{5 - (-1)}{2 - (-4)} = 1. Substitute (−4,−1)(-4, -1): −1=1(−4)+b-1 = 1(-4) + b, so b=3b = 3. The equation is y=x+3y = x + 3.

Buzzer beatermedium

A line passes through the points (2,−3)(2, -3) and (6,1)(6, 1). Which equation represents this line in slope-intercept form?

The slope is m=1−(−3)6−2=1m = \dfrac{1 - (-3)}{6 - 2} = 1. Substitute (2,−3)(2, -3): −3=1(2)+b-3 = 1(2) + b, so b=−5b = -5. The equation is y=x−5y = x - 5.

Overtime

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