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Occurrence and Preparation of the Representative Metals Quiz

12 questions chemistry Grades 9-12

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  1. Why are most representative metals NOT found as free elements in nature?

    • Because of their reactivity
    • Because they are too dense
    • Because they are gaseous
    • Because they are radioactive
    Reveal answer

    Answer: Because of their reactivity

    Source evidence

    PDF page 962: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  2. Where are sodium and potassium primarily found?

    • In sulfide ores
    • In carbonates only
    • Only in seawater
    • In salt deposits and silicates
    Reveal answer

    Answer: In salt deposits and silicates

    Source evidence

    PDF page 962: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  3. Beryllium occurs as which mineral?

    • Cassiterite
    • Cryolite
    • Bauxite
    • Beryl, Be3Al2Si6O18
    Reveal answer

    Answer: Beryl, Be3Al2Si6O18

    Source evidence

    PDF page 962: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  4. Aluminum occurs abundantly in clay and in what impure ore?

    • Cassiterite
    • Beryl
    • Cryolite
    • Bauxite
    Reveal answer

    Answer: Bauxite

    Source evidence

    PDF page 962: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  5. What is the principal tin ore?

    • Galena
    • Bauxite
    • Cassiterite, SnO2
    • Beryl
    Reveal answer

    Answer: Cassiterite, SnO2

    Source evidence

    PDF page 962: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  6. Ions of groups 1 and 2 metals and aluminum are prepared by what process?

    • Chemical reduction
    • Filtration
    • Distillation
    • Electrolysis
    Reveal answer

    Answer: Electrolysis

    Source evidence

    PDF page 962: Ions of metals in of groups 1 and 2, along with aluminum, are very difficult to reduce; therefore, it is necessary to prepare these elements by electrolysis, an important process discussed in the chapter on electrochemistry. Briefly, electrolysis involves using electrical energy to drive unfavorable chemical reactions to completion; it is useful in the isolation of reactive metals in their pure forms. Sodium, aluminum, and magnesium are typical examples.

  7. What does electrolysis use to drive unfavorable reactions to completion?

    • Heat only
    • Electrical energy
    • High pressure
    • A reducing agent
    Reveal answer

    Answer: Electrical energy

    Source evidence

    PDF page 962: Ions of metals in of groups 1 and 2, along with aluminum, are very difficult to reduce; therefore, it is necessary to prepare these elements by electrolysis, an important process discussed in the chapter on electrochemistry. Briefly, electrolysis involves using electrical energy to drive unfavorable chemical reactions to completion; it is useful in the isolation of reactive metals in their pure forms. Sodium, aluminum, and magnesium are typical examples.

  8. What is the cell used to produce sodium by electrolysis called?

    • Pidgeon cell
    • Galvanic cell
    • Downs cell
    • Hall–Héroult cell
    Reveal answer

    Answer: Downs cell

    Source evidence

    PDF page 962: The Preparation of Sodium The most important method for the production of sodium is the electrolysis of molten sodium chloride; the set-up is a Downs cell, shown in Figure 18.10. The reaction involved in this process is: electrolysis

  9. Why is calcium chloride added to molten NaCl in the Downs cell?

    • To raise the boiling point
    • To lower the melting point to 600 °C
    • To act as a reducing agent
    • To increase density
    Reveal answer

    Answer: To lower the melting point to 600 °C

    Source evidence

    PDF page 962: 2 600 °C The electrolysis cell contains molten sodium chloride (melting point 801 °C), to which calcium chloride has been added to lower the melting point to 600 °C (a colligative effect). The passage of a direct current through the cell

  10. In the Downs cell, sodium ions migrate to which electrode and are reduced?

    • The positively charged anode
    • The collector tank
    • The neutral electrode
    • The negatively charged cathode
    Reveal answer

    Answer: The negatively charged cathode

    Source evidence

    PDF page 963: causes the sodium ions to migrate to the negatively charged cathode and pick up electrons, reducing the ions to sodium metal. Chloride ions migrate to the positively charged anode, lose electrons, and undergo oxidation to chlorine gas. The overall cell reaction comes from adding the following reactions: + − at the cathode: 2Na + 2e ⟶ 2Na(l) − − at the anode: 2Cl ⟶ Cl (g) + 2e 2 + − overall change: 2Na + 2Cl ⟶ 2Na(l) + Cl (g) 2 Separation of the molten sodium and chlorine prevents recombination. The liquid sodium, which is less dense than molten sodium chloride, floats to the surface and flows into a collector. The gaseous chlorine goes to storage tanks. Chlorine is also a valuable product.

  11. Why can't sodium be isolated by electrolysis of aqueous sodium salts?

    • The solution is too dilute
    • Hydrogen ions are more easily reduced
    • Chlorine gas forms first
    • Sodium dissolves in water
    Reveal answer

    Answer: Hydrogen ions are more easily reduced

    Source evidence

    PDF page 963: possible to isolate sodium by electrolysis of aqueous solutions of sodium salts because hydrogen ions are more easily reduced than are sodium ions; as a result, hydrogen gas forms at the cathode instead of the desired sodium metal. The high temperature required to melt NaCl means that liquid sodium metal forms.

  12. Who invented the process used to prepare aluminum in 1886?

    • Paul Héroult
    • Charles M. Hall
    • Le Châtelier
    • Charles Downs
    Reveal answer

    Answer: Charles M. Hall

    Source evidence

    PDF page 963: The Preparation of Aluminum The preparation of aluminum utilizes a process invented in 1886 by Charles M. Hall, who began to work on the problem while a student at Oberlin College in Ohio. Paul L. T. Héroult discovered the process independently a month or two later in France. In honor to the two inventors, this electrolysis cell is known as the Hall–Héroult cell. The Hall–Héroult cell is an electrolysis cell for the production of aluminum. Figure 18.11 illustrates the Hall–Héroult cell. The production of aluminum begins with the purification of bauxite, the most common source of aluminum. The reaction of bauxite, AlO(OH), with hot sodium hydroxide forms soluble sodium aluminate, while clay and other impurities remain undissolved: AlO(OH)(s) + NaOH(aq) + H O(l) ⟶ Na[Al(OH) ](aq) 2 4 After the removal of the impurities by filtration, the addition of acid to the aluminate leads to the reprecipitation of aluminum hydroxide: + + Na[Al(OH) ](aq) + H O (aq) ⟶ Al(OH) (s) + Na (aq) + 2H O(l) 4 2 3 3 The next step is to remove the precipitated aluminum hydroxide by filtration. Heating the hydroxide produces

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