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Occurrence and Preparation of the Representative Metals Quiz

12 questions chemistry Grades 9-12

The question sheet

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  1. Why are most representative metals not found as free elements in nature?

    • Their reactivity
    • Their radioactivity
    • Their low melting points
    • Their high density
    Reveal answer

    Answer: Their reactivity

    Source evidence

    PDF page 986: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  2. Where are sodium and potassium primarily found?

    • Phosphate minerals
    • Salt deposits and silicates
    • Seawater only
    • Bauxite deposits
    Reveal answer

    Answer: Salt deposits and silicates

    Source evidence

    PDF page 986: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  3. What is the principal tin ore?

    • Cassiterite, SnO2
    • Bauxite
    • Cryolite
    • Beryl
    Reveal answer

    Answer: Cassiterite, SnO2

    Source evidence

    PDF page 986: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  4. Which metal is found abundantly in bauxite?

    • Magnesium
    • Lithium
    • Aluminum
    • Sodium
    Reveal answer

    Answer: Aluminum

    Source evidence

    PDF page 986: Because of their reactivity, we do not find most representative metals as free elements in nature. However, compounds that contain ions of most representative metals are abundant. In this section, we will consider the two common techniques used to isolate the metals from these compounds—electrolysis and chemical reduction. These metals primarily occur in minerals, with lithium found in silicate or phosphate minerals, and sodium and potassium found in salt deposits from evaporation of ancient seas and in silicates. The alkaline earth metals occur as silicates and, with the exception of beryllium, as carbonates and sulfates. Beryllium occurs as the mineral beryl, Be3Al2Si6O18, which, with certain impurities, may be either the gemstone emerald or aquamarine. Magnesium is in seawater and, along with the heavier alkaline earth metals, occurs as silicates, carbonates, and sulfates. Aluminum occurs abundantly in many types of clay and in bauxite, an impure aluminum oxide hydroxide. The principle tin ore is the oxide cassiterite, SnO2, and the principle lead and thallium ores are the sulfides or the products of weathering of the sulfides. The remaining representative metals occur as impurities in zinc or aluminum ores.

  5. The most important method for producing sodium is electrolysis of what?

    • Molten sodium chloride
    • Sodium hydroxide
    • Sodium silicate
    • Aqueous sodium chloride
    Reveal answer

    Answer: Molten sodium chloride

    Source evidence

    PDF page 986: The Preparation of Sodium The most important method for the production of sodium is the electrolysis of molten sodium chloride; the set-up is a

  6. What cell is used for the electrolysis of molten sodium chloride?

    • Pidgeon cell
    • Galvanic cell
    • Hall–Héroult cell
    • Downs cell
    Reveal answer

    Answer: Downs cell

    Source evidence

    PDF page 987: Downs cell, shown in Figure 18.10. The reaction involved in this process is: electrolysis

  7. Why is calcium chloride added to molten sodium chloride?

    • To produce oxygen
    • To increase conductivity
    • To lower the melting point
    • To act as a reducing agent
    Reveal answer

    Answer: To lower the melting point

    Source evidence

    PDF page 987: 2 600 °C The electrolysis cell contains molten sodium chloride (melting point 801 °C), to which calcium chloride has been added to lower the melting point to 600 °C (a colligative effect). The passage of a direct current through the cell causes the sodium ions to migrate to the negatively charged cathode and pick up electrons, reducing the ions to sodium metal. Chloride ions migrate to the positively charged anode, lose electrons, and undergo oxidation to chlorine gas. The overall cell reaction comes from adding the following reactions: + − at the cathode: 2Na + 2e ⟶ 2Na(l) − − at the anode: 2Cl ⟶ Cl (g) + 2e 2 + − overall change: 2Na + 2Cl ⟶ 2Na(l) + Cl (g) 2 Separation of the molten sodium and chlorine prevents recombination. The liquid sodium, which is less dense than molten sodium chloride, floats to the surface and flows into a collector. The gaseous chlorine goes to storage tanks. Chlorine is also a valuable product.

  8. At the cathode in the Downs cell, sodium ions are:

    • Reduced to sodium metal
    • Oxidized to Na+
    • Converted to chlorine
    • Evaporated
    Reveal answer

    Answer: Reduced to sodium metal

    Source evidence

    PDF page 987: 2 600 °C The electrolysis cell contains molten sodium chloride (melting point 801 °C), to which calcium chloride has been added to lower the melting point to 600 °C (a colligative effect). The passage of a direct current through the cell causes the sodium ions to migrate to the negatively charged cathode and pick up electrons, reducing the ions to sodium metal. Chloride ions migrate to the positively charged anode, lose electrons, and undergo oxidation to chlorine gas. The overall cell reaction comes from adding the following reactions: + − at the cathode: 2Na + 2e ⟶ 2Na(l) − − at the anode: 2Cl ⟶ Cl (g) + 2e 2 + − overall change: 2Na + 2Cl ⟶ 2Na(l) + Cl (g) 2 Separation of the molten sodium and chlorine prevents recombination. The liquid sodium, which is less dense than molten sodium chloride, floats to the surface and flows into a collector. The gaseous chlorine goes to storage tanks. Chlorine is also a valuable product.

  9. Why can sodium not be isolated by electrolysis of aqueous sodium salts?

    • Chlorine forms at cathode
    • Sodium dissolves in water
    • Water freezes
    • Hydrogen ions are more easily reduced
    Reveal answer

    Answer: Hydrogen ions are more easily reduced

    Source evidence

    PDF page 987: possible to isolate sodium by electrolysis of aqueous solutions of sodium salts because hydrogen ions are more easily reduced than are sodium ions; as a result, hydrogen gas forms at the cathode instead of the desired sodium metal. The high temperature required to melt NaCl means that liquid sodium metal forms.

  10. Who invented the process for preparing aluminum in 1886?

    • Pidgeon
    • Paul Héroult
    • Charles M. Hall
    • Downs
    Reveal answer

    Answer: Charles M. Hall

    Source evidence

    PDF page 987: The Preparation of Aluminum The preparation of aluminum utilizes a process invented in 1886 by Charles M. Hall, who began to work on the problem while a student at Oberlin College in Ohio. Paul L. T. Héroult discovered the process independently a month or two later in France. In honor to the two inventors, this electrolysis cell is known as the Hall–Héroult cell. The Hall–Héroult cell is an electrolysis cell for the production of aluminum. Figure 18.11 illustrates the Hall–Héroult cell. The production of aluminum begins with the purification of bauxite, the most common source of aluminum. The reaction of bauxite, AlO(OH), with hot sodium hydroxide forms soluble sodium aluminate, while clay and other impurities remain undissolved: AlO(OH)(s) + NaOH(aq) + H O(l) ⟶ Na[Al(OH) ](aq) 2 4

  11. The reaction of bauxite with hot sodium hydroxide forms what soluble product?

    • Cryolite
    • Aluminum chloride
    • Aluminum oxide
    • Sodium aluminate
    Reveal answer

    Answer: Sodium aluminate

    Source evidence

    PDF page 987: The Preparation of Aluminum The preparation of aluminum utilizes a process invented in 1886 by Charles M. Hall, who began to work on the problem while a student at Oberlin College in Ohio. Paul L. T. Héroult discovered the process independently a month or two later in France. In honor to the two inventors, this electrolysis cell is known as the Hall–Héroult cell. The Hall–Héroult cell is an electrolysis cell for the production of aluminum. Figure 18.11 illustrates the Hall–Héroult cell. The production of aluminum begins with the purification of bauxite, the most common source of aluminum. The reaction of bauxite, AlO(OH), with hot sodium hydroxide forms soluble sodium aluminate, while clay and other impurities remain undissolved: AlO(OH)(s) + NaOH(aq) + H O(l) ⟶ Na[Al(OH) ](aq) 2 4

  12. Aluminum oxide dissolves in a molten mixture of cryolite and what?

    • Carbon
    • Silicon
    • Calcium fluoride
    • Sodium chloride
    Reveal answer

    Answer: Calcium fluoride

    Source evidence

    PDF page 988: After the removal of the impurities by filtration, the addition of acid to the aluminate leads to the reprecipitation of aluminum hydroxide: + + Na[Al(OH) ](aq) + H O (aq) ⟶ Al(OH) (s) + Na (aq) + 2H O(l) 4 3 3 2 The next step is to remove the precipitated aluminum hydroxide by filtration. Heating the hydroxide produces aluminum oxide, Al2O3, which dissolves in a molten mixture of cryolite, Na3AlF6, and calcium fluoride, CaF2. Electrolysis of this solution takes place in a cell like that shown in Figure 18.11. Reduction of aluminum ions to the metal occurs at the cathode, while oxygen, carbon monoxide, and carbon dioxide form at the anode.

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