Spectroscopic and Magnetic Properties of Coordination Compounds Quiz
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Which model explains the colors, magnetic behavior, and some structures of transition metal complexes?
- Molecular orbital theory
- Kinetic theory
- Valence bond theory
- Crystal field theory
Reveal answer
Answer: Crystal field theory
Source evidence
PDF page 1069: To explain the observed behavior of transition metal complexes (such as how colors arise), a model involving electrostatic interactions between the electrons from the ligands and the electrons in the unhybridized d orbitals of the central metal atom has been developed. This electrostatic model is crystal field theory (CFT). It allows us to understand, interpret, and predict the colors, magnetic behavior, and some structures of coordination compounds of
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In crystal field theory, both the ligand and the metal are treated as:
- Neutral atoms
- Covalent bonds
- Magnetic dipoles
- Point charges
Reveal answer
Answer: Point charges
Source evidence
PDF page 1070: ions. Both the ligand and the metal are treated as infinitesimally small point charges. All electrons are negative, so the electrons donated from the ligands will repel the electrons of the central metal. Let us consider the behavior of the electrons in the unhybridized d orbitals in an octahedral complex. The five d orbitals consist of lobe-shaped regions and are arranged in space, as shown in Figure 19.33. In an octahedral complex, the six ligands coordinate along the axes.
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In an octahedral complex, which orbitals point directly at the ligands?
- The t2g orbitals
- The p orbitals
- The s orbitals
- The eg orbitals
Reveal answer
Answer: The eg orbitals
Source evidence
PDF page 1070: In an uncomplexed metal ion in the gas phase, the electrons are distributed among the five d orbitals in accord with Hund's rule because the orbitals all have the same energy. However, when ligands coordinate to a metal ion, the energies of the d orbitals are no longer the same. In octahedral complexes, the lobes in two of the five d orbitals, the d 2 and d 2 2 orbitals, point toward the ligands x −y z (Figure 19.33). These two orbitals are called the eg orbitals (the symbol actually refers to the symmetry of the orbitals, but we will use it as a convenient name for these two orbitals in an octahedral complex). The other three orbitals, the dxy, dxz, and dyz orbitals, have lobes that point between the ligands and are called the t2g orbitals (again, the symbol really refers to the symmetry of the orbitals). As six ligands approach the metal ion along the axes of the octahedron, their point charges repel the electrons in the d orbitals of the metal ion. However, the repulsions between the electrons in the e orbitals (the d 2 and d 2 2 orbitals) and the ligands are greater than the repulsions between
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In octahedral complexes, the eg orbitals are:
- Higher in energy than t2g
- Equal in energy to t2g
- Nonexistent
- Lower in energy than t2g
Reveal answer
Answer: Higher in energy than t2g
Source evidence
PDF page 1071: Figure 19.34 In octahedral complexes, the eg orbitals are destabilized (higher in energy) compared to the t2g orbitals
PDF page 1070: g x −y z the electrons in the t2g orbitals (the dzy, dxz, and dyz orbitals) and the ligands. This is because the lobes of the eg orbitals point directly at the ligands, whereas the lobes of the t2g orbitals point between them. Thus, electrons in the eg orbitals of the metal ion in an octahedral complex have higher potential energies than those of electrons in the t2g orbitals. The difference in energy may be represented as shown in Figure 19.34.
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The difference in energy between eg and t2g orbitals is called:
- Bond energy
- Pairing energy
- Crystal field splitting
- Activation energy
Reveal answer
Answer: Crystal field splitting
Source evidence
PDF page 1071: The difference in energy between the eg and the t2g orbitals is called the crystal field splitting and is symbolized by Δoct, where oct stands for octahedral. The magnitude of Δoct depends on many factors, including the nature of the six ligands located around the central metal ion, the charge on the metal, and whether the metal is using 3d, 4d, or 5d orbitals. Different ligands produce different crystal field splittings. The increasing crystal field splitting produced by ligands is expressed in the spectrochemical series, a short version of which is given here: − − − − 2− − −
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Ligands on the left of the spectrochemical series are described as:
- Weak-field ligands
- Bidentate ligands
- Neutral ligands
- Strong-field ligands
Reveal answer
Answer: Weak-field ligands
Source evidence
PDF page 1071: < NH < en < NO < CN 2 2 4 3 2 ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→ a few ligands of the spectrochemical series, in order of increasing field trength of the ligand In this series, ligands on the left cause small crystal field splittings and are weak-field ligands, whereas those on the right cause larger splittings and are strong-field ligands. Thus, the Δoct value for an octahedral complex with iodide
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According to the spectrochemical series, which produces a larger splitting than iodide?
- Nothing does
- Cyanide (CN)
- Bromide
- No difference
Reveal answer
Answer: Cyanide (CN)
Source evidence
PDF page 1071: < NH < en < NO < CN 2 2 4 3 2 ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯→ a few ligands of the spectrochemical series, in order of increasing field trength of the ligand In this series, ligands on the left cause small crystal field splittings and are weak-field ligands, whereas those on the right cause larger splittings and are strong-field ligands. Thus, the Δoct value for an octahedral complex with iodide
PDF page 1071: ligands (I ) is much smaller than the Δoct value for the same metal with cyanide ligands (CN ). Electrons in the d orbitals follow the aufbau (“filling up”) principle, which says that the orbitals will be filled to give the lowest total energy, just as in main group chemistry. When two electrons occupy the same orbital, the like charges repel each other. The energy needed to pair up two electrons in a single orbital is called the pairing energy (P). Electrons will always singly occupy each orbital in a degenerate set before pairing. P is similar in magnitude to Δoct. When electrons fill the d orbitals, the relative magnitudes of Δoct and P determine which orbitals will be occupied.
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The energy needed to pair two electrons in a single orbital is called:
- Lattice energy
- Crystal field splitting
- Ionization energy
- Pairing energy (P)
Reveal answer
Answer: Pairing energy (P)
Source evidence
PDF page 1071: ligands (I ) is much smaller than the Δoct value for the same metal with cyanide ligands (CN ). Electrons in the d orbitals follow the aufbau (“filling up”) principle, which says that the orbitals will be filled to give the lowest total energy, just as in main group chemistry. When two electrons occupy the same orbital, the like charges repel each other. The energy needed to pair up two electrons in a single orbital is called the pairing energy (P). Electrons will always singly occupy each orbital in a degenerate set before pairing. P is similar in magnitude to Δoct. When electrons fill the d orbitals, the relative magnitudes of Δoct and P determine which orbitals will be occupied.
PDF page 1080: pairing energy (P) energy required to place two electrons with opposite spins into a single orbital
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Complexes with electrons paired due to large crystal field splitting are called:
- Chelates
- Low-spin complexes
- Diamagnetic ligands
- High-spin complexes
Reveal answer
Answer: Low-spin complexes
Source evidence
PDF page 1071: require less energy to pair than they require to be excited to the eg orbitals (Δoct > P). The six 3d electrons of the Fe ion pair in the three t2g orbitals (Figure 19.35). Complexes in which the electrons are paired because of the large crystal field splitting are called low-spin complexes because the number of unpaired electrons (spins) is minimized.
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In [Fe(H2O)6], the weak field of water produces a splitting where:
- Δoct is less than P
- Δoct equals zero
- Δoct is greater than P
- P equals zero
Reveal answer
Answer: Δoct is less than P
Source evidence
PDF page 1072: In [Fe(H2O)6] , on the other hand, the weak field of the water molecules produces only a small crystal field splitting (Δoct < P). Because it requires less energy for the electrons to occupy the eg orbitals than to pair together, there will be an electron in each of the five 3d orbitals before pairing occurs. For the six d electrons on the iron(II) center in
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How many unpaired electrons does high-spin [Fe(H2O)6] have?
- Two
- Zero
- Five
- One
Reveal answer
Answer: Five
Source evidence
PDF page 1072: A similar line of reasoning shows why the [Fe(CN)6] ion is a low-spin complex with only one unpaired electron,
PDF page 1072: whereas both the [Fe(H2O)6] and [FeF6] ions are high-spin complexes with five unpaired electrons.
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Because Δtet is small, all tetrahedral complexes are:
- High spin
- Diamagnetic
- Low spin
- Colorless
Reveal answer
Answer: High spin
Source evidence
PDF page 1073: Explain how many unpaired electrons a tetrahedral d ion will have. Answer: 4; because Δtet is small, all tetrahedral complexes are high spin and the electrons go into the t2
Chemistry 2e
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