RICAS Grades 6-8 Expressions and Equations. Practice it free.

Let $x$ be the total area. Vegetables and flowers cover $\dfrac{1}{4}x + \dfrac{1}{5}x = \dfrac{9}{20}x$. The herbs and fruit trees cover $48 + 40 = 88$ square meters, so $\dfrac{11}{20}x = 88$ and $x = 160$.

The constants $12$ and $5$ are like terms: $12 + 5 = 17$. The term $p$ stays the same, so the expression is equivalent to $p + 17\textsf{.}$

Combine $x$-terms: $8x + 8x = 16x$. Combine constants: $2 - 1 = 1$. Result: $16x + 1$.

$2^{6} = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 64\textsf{.}$

The base $4$ appears $2$ times as a factor, so $4 \times 4 = 4^{2}$.

Both equations have slope $6$ but different $y$-intercepts ($1$ and $-4$), so the lines are parallel and the system has no solution.

The bag must weigh at most $50.0$ pounds. The minimum decrease is $52.8 - 50.0 = 2.8\textsf{.}$

Rewrite in slope-intercept form: $y = -\dfrac{1}{3}x + \dfrac{4}{3}$ and $y = -\dfrac{1}{3}x + \dfrac{4}{3}$. The slopes and $y$-intercepts match, so the equations describe the same line and the system has infinitely many solutions.