SC READY Grade 7 Data, Probability, and Statistical Reasoning. Practice it free.

Analyze data sets to identify their statistical elements; calculate and interpret probability. This Grade 7 reporting domain maps to 4 practice skills and 8 representative questions from the playable bank.

Grade 7DPSR4 mapped skills
What the test measures

Data, Probability, and Statistical Reasoning skills

  1. 7.DPSR.1.1 to 1.4

  2. 7.DPSR.2.1 to 2.4

Standards basis

2025 South Carolina College- and Career-Ready Mathematics Standards — South Carolina

How the SC READY reports it

SC READY is South Carolina’s state assessment program and does not use a national blueprinted framework like SBAC or NAEP. Its math tests are aligned to the 2025 South Carolina College- and Career-Ready Mathematics Standards and organized into state-specific reporting categories.

Blueprint & weighting

The blueprint publishes approximate item-count ranges by reporting category, not percentages. Grade 3: DPSR 7-10, MGSR 15-18, NR 15-18, PAFR 9-13; Grade 4: DPSR 7-9, MGSR 12-15, NR 12-15, PAFR 15-19; Grade 5: DPSR 8-10, MGSR 11-14, NR 9-11, PAFR 17-21; Grade 6: DPSR 9-11, MGSR 11-14, NR 7-9, PAFR 18-21; Grade 7: DPSR 11-14, MGSR 13-17, NR 6-8, PAFR 14-18; Grade 8: DPSR 8-10, MGSR 15-19, NR 7-9, PAFR 14-18. All grades are 50 operational items, with additional field-test items; DOK ranges are 15-40% level 1, 55-85% level 2, and 0-10% level 3.

Try it now

8 free questions · 0/0 correct

Practice playeasy

What is the probability of the spinner landing on a shaded section (5 of 8)? Give a simplified fraction.

P=favorabletotal=58=58P = \dfrac{\text{favorable}}{\text{total}} = \dfrac{5}{8} = \dfrac{5}{8}.

Practice playeasy

A bowl contains 44 lemons and 99 limes. One piece of fruit is chosen at random. What is the probability that the fruit is a lime?

There are 4+9=134 + 9 = 13 pieces of fruit and 99 are limes, so P(lime)=913P(\text{lime}) = \dfrac{9}{13}.

Practice playeasy

A number cube is rolled once. What is the probability of rolling an even number?

Three of the six faces (2,4,62, 4, 6) are even, so P=36=12P = \dfrac{3}{6} = \dfrac{1}{2}.

Practice playeasy

The whole numbers 11 through 2424 were each written on separate cards. Those 2424 cards were placed in a hat. One card will be randomly drawn from this hat. What is the probability that the card will show a number greater than 1515?

Numbers greater than 1515 from 11 to 2424 are 16,17,18,19,20,21,22,23,2416, 17, 18, 19, 20, 21, 22, 23, 24, giving 99 favorable outcomes: P=924=38P = \tfrac{9}{24} = \tfrac{3}{8}.

Practice playeasy

A bag holds 44 red marbles and 55 green marbles. One marble is drawn at random. What is the probability it is green? Give a simplified fraction.

There are 4+5=94 + 5 = 9 marbles in all and 55 are green, so P(green)=59P(\text{green}) = \dfrac{5}{9}.

Practice playeasy

A standard six-sided number cube is rolled once. What is the probability of rolling an odd number?

The odd faces are 11, 33, and 55, so P(odd)=36=12P(\text{odd}) = \dfrac{3}{6} = \dfrac{1}{2}.

Practice playeasy

A standard die is rolled. What is the probability of not rolling a 66?

Five of the six faces are not 66, so P=116=56P = 1 - \dfrac{1}{6} = \dfrac{5}{6}.

Practice playeasy

The whole numbers 11 through 2424 were each written on separate cards. Those 2424 cards were placed in a bag. One card will be randomly drawn from this bag. What is the probability that the card will show a number divisible by 44?

Multiples of 44 from 11 to 2424 are 4,8,12,16,20,244, 8, 12, 16, 20, 24, so there are 66 favorable outcomes: P=624=14P = \tfrac{6}{24} = \tfrac{1}{4}.

Keep practicing

Turn data, probability, and statistical reasoning into game time.

The SC READY placement starts with this test's real coverage map and finds the right difficulty.