8.F.B.4 Math Practice Questions — Sports Academy Games

Practice playeasy

What is the slope of the line $y = x - 7$ ?

In $y = mx + b$ , the slope is $m = 1$ .

Practice playmedium

In the rule $g(x) = 8x + c$ , the value of $c$ is a constant. Given that $g(3) = 10$ , find $g(5)$ .

Substitute $x = 3$ : $8(3) + c = 10$ , so $24 + c = 10$ and $c = -14$ . The rule is $g(x) = 8x - 14$ , so $g(5) = 8(5) - 14 = 40 - 14 = 26$ .

Practice playeasy

A gym charges a $\text{\char36}30$ monthly membership plus $\text{\char36}5$ for each fitness class. Let $x$ be the number of classes and $y$ be the total monthly cost in dollars. Which equation models the situation?

Each class adds $\text{\char36}5$ (slope) on top of the $\text{\char36}30$ membership (intercept), so $y = 5x + 30\textsf{.}$

Practice playeasy

What is the slope of the line through $(1, 2)$ and $(3, 8)$ ?

Slope $= \dfrac{8 - 2}{3 - 1} = \dfrac{6}{2} = 3\textsf{.}$

Practice playeasy

What is the $y$ -intercept of the line $y = \dfrac{1}{2}x - 4$ ?

In $y = mx + b$ , the $y$ -intercept is $b = -4$ .

Practice playmedium

Let $p(x) = kx - 6$ for some constant $k$ . If $p(2) = 10$ , what is the value of $p(5)$ ?

Substitute $x = 2$ : $2k - 6 = 10$ , so $2k = 16$ and $k = 8$ . The rule is $p(x) = 8x - 6$ , so $p(5) = 8(5) - 6 = 40 - 6 = 34$ .

Practice playeasy

An amusement park charges $\text{\char36}12$ for admission and $\text{\char36}3$ for each ride. Let $x$ be the number of rides and $y$ be the total cost in dollars. Which equation models the situation?

Admission is the starting cost ( $\text{\char36}12$ ) and each ride adds $\text{\char36}3$ , so $y = 3x + 12\textsf{.}$

Practice playeasy

What is the slope of the line through $(0, 5)$ and $(4, -3)$ ?

Slope $= \dfrac{-3 - 5}{4 - 0} = \dfrac{-8}{4} = -2\textsf{.}$

8.F.B.4 math practice. Learn by doing.

Skills aligned to 8.F.B.4

Graphing linear equations

Linear functions with an unknown constant

Modeling linear situations (ACT/SAT/PSAT 8/9/10)

Slope formula

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Practice 8.F.B.4 inside a game.