Star Math probability. Practice it free.

Measures probability reasoning and estimation. This All grades reporting domain maps to 7 practice skills and 8 representative questions from the playable bank.

Grades K–127 mapped skills
What the test measures

probability skills

  1. make estimates and determine probabilities

Standards basis

Research-based, state-specific learning progressions aligned to state grade-level math standards (CCSS-like strands are visible on the product page) — national

How the Star Math reports it

Star Math is Renaissance’s proprietary adaptive assessment, not a shared framework like SBAC or NAEP. The page describes research-based, state-specific learning progressions aligned to English and Spanish, rather than a single common external blueprint.

Blueprint & weighting

Star Math uses the Independent / state-specific framework (strands structure).

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8 free questions · 0/0 correct

Practice playeasy

For two independent events, the probability of an even roll then a head: P(A)=36P(A)=\tfrac{3}{6}, P(B)=12P(B)=\tfrac{1}{2}. Find P(A and B)P(A \text{ and } B) as a simplified fraction.

Multiply: P(A and B)=36×12=14P(A \text{ and } B) = \tfrac{3}{6} \times \tfrac{1}{2} = \tfrac{1}{4}.

Practice playeasy

From a table, 4 are plants that flower AND got fertilizer and 16 total are plants that got fertilizer. Find the conditional probability of flowering given fertilized (simplified fraction).

P(AB)=P(A and B)P(B)=416=14P(A\mid B) = \dfrac{P(A \text{ and } B)}{P(B)} = \dfrac{4}{16} = \dfrac{1}{4}.

Practice playeasy

A game spinner is divided into 1212 equal sections. Exactly 44 sections are gold and the rest are silver. What is the probability that the spinner lands on gold on one spin?

P(gold)=412=13P(\text{gold}) = \dfrac{4}{12} = \dfrac{1}{3}.

Practice playeasy

A standard six-sided die is rolled once. What is the probability of rolling a 44?

Exactly one of the 66 equally likely faces shows a 44, so the probability is 16\dfrac{1}{6}.

Practice playeasy

The whole numbers 11 through 2424 were each written on separate slips of paper. Those 2424 slips were placed in a box. One slip will be randomly drawn from this box. What is the probability that the slip will show a factor of 2424?

Factors of 2424 from 11 to 2424 are 1,2,3,4,6,8,12,241, 2, 3, 4, 6, 8, 12, 24, giving 88 favorable outcomes: P=824=13P = \tfrac{8}{24} = \tfrac{1}{3}.

Practice playeasy

What is the probability of drawing an Ace from a deck? Give a simplified fraction.

P=favorabletotal=452=113P = \dfrac{\text{favorable}}{\text{total}} = \dfrac{4}{52} = \dfrac{1}{13}.

Practice playmedium

A game spinner has 66 equal sections numbered 11 through 66. The spinner is spun twice. What is the probability that both spins land on a number greater than 44?

P(greater than 4)=26=13P(\text{greater than }4) = \dfrac{2}{6} = \dfrac{1}{3} on each spin. The spins are independent, so P(both)=13×13=19P(\text{both}) = \dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}.

Practice playeasy

A meal has 3 mains and 4 sides. How many different (main, side) combinations are possible?

By the multiplication principle: 3×4=123 \times 4 = 12.

Keep practicing

Turn probability into game time.

The Star Math placement starts with this test's real coverage map and finds the right difficulty.