AASA Grade 7 Geometry. Practice it free.

Draw, construct, and describe geometrical figures and describe the relationships between them. This Grade 7 reporting domain maps to 8 practice skills and 8 representative questions from the playable bank.

Grade 78 mapped skills
What the test measures

Geometry skills

  1. Solve problems involving scale drawings of geometric figures

  2. Draw geometric shapes with given conditions

  3. Describe the two-dimensional figures that result from slicing three-dimensional figures

  4. Solve real-world and mathematical problems involving area, surface area, and volume

Standards basis

Arizona 2016 Mathematics Standards — Arizona

How the AASA reports it

AASA is Arizona’s statewide achievement test for Grades 3-8, and its math item specifications are aligned to Arizona’s 2016 Mathematics Standards rather than a national framework like SBAC or SAT. The public AASA page does not show a fixed common-core-style domain blueprint; instead, the official math coverage is embedded in grade-level item specifications and scoring guides.

Blueprint & weighting

AASA uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

Similar triangles STUSTU and VWXVWX have areas 3636 and 9.9\textsf{.} Side STST corresponds to side VW,VW\textsf{,} and ST=12.ST = 12\textsf{.} What is the length of VW?VW\textsf{?}

The scale factor from STU\triangle STU to VWX\triangle VWX satisfies k2=936=14,k^{2} = \dfrac{9}{36} = \dfrac{1}{4}\textsf{,} so k=12.k = \dfrac{1}{2}\textsf{.} Then VW=1212=6.VW = 12 \cdot \dfrac{1}{2} = 6\textsf{.}

Practice playhard

A rectangular prism has volume 7272 cubic centimeters and height 44 centimeters. The length is twice the width. What is the width, in centimeters?

V=whV = \ell w h and =2w\ell = 2w, so 72=(2w)(w)(4)=8w272 = (2w)(w)(4) = 8w^2. Then w2=9w^2 = 9 and w=3 cm.w = 3\text{ cm}\textsf{.}

Practice playmedium

A shipping company uses closed rectangular cartons that measure 66 centimeters by 44 centimeters by 55 centimeters. What is the total exterior surface area, in square centimeters, of one carton?

Use SA=2lw+2lh+2whSA = 2lw + 2lh + 2wh with l=6l = 6, w=4w = 4, and h=5h = 5. Then SA=2(6)(4)+2(6)(5)+2(4)(5)=48+60+40=148SA = 2(6)(4) + 2(6)(5) + 2(4)(5) = 48 + 60 + 40 = 148 square centimeters.

Practice playeasy

Find the surface area of a sphere with radius 11. Use π=3\pi = 3.

SA=4πr2=4×3×1=12SA = 4 \pi r^{2} = 4 \times 3 \times 1 = 12.

Practice playeasy

A cylinder has r2=9r^2 = 9 and height 33. Using π=3\pi = 3, what is its volume?

V=πr2h=3×9×3=81V = \pi r^2 h = 3 \times 9 \times 3 = 81.

Practice playeasy

A circle has a radius of 88 inches. What is the circumference, in inches, of the circle?

The circumference of a circle is C=2πrC = 2\pi r. Substitute r=8r = 8: C=2π(8)=16π.C = 2\pi(8) = 16\pi\textsf{.}

Practice playeasy

A circle has diameter 66. Using π=3\pi = 3, what is its circumference?

C=πd=3×6=18C = \pi d = 3 \times 6 = 18.

Practice playmedium

In a triangle, two sides each have length 10.10\textsf{.} Which inequality represents the possible lengths, x,x\textsf{,} of the third side?

The triangle inequality requires 1010<x<10+10.|10 - 10| < x < 10 + 10\textsf{.} Simplifying gives 0<x<20.0 < x < 20\textsf{.}

Keep practicing

Turn geometry into game time.

The AASA placement starts with this test's real coverage map and finds the right difficulty.