HSG.GMD.A.3 math practice. Learn by doing.

HSG.GMD.A.3 practice covers use volume formulas for cylinders, pyramids, cones, and spheres to solve problems. Work through 8 free questions with answers and explanations, then continue in the related math games.

Grade 9Grade 102 mapped skills
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8 free questions · 0/0 correct

Practice playeasy

Find the volume of a cone with radius 33 and height 55. Use π=3\pi = 3.

V=13πr2h=13×3×9×5=45V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3} \times 3 \times 9 \times 5 = 45.

Practice playeasy

A storage shed is shaped like a rectangular prism that is 1212 feet long, 88 feet wide, and 55 feet tall. What is the volume of the shed's interior, in cubic feet?

For a rectangular prism, V=wh=12×8×5=480V = \ell w h = 12 \times 8 \times 5 = 480 cubic feet.

Practice playeasy

Find the volume of a cylinder with radius 33 and height 22. Use π=3\pi = 3.

V=πr2h=3×9×2=54V = \pi r^{2} h = 3 \times 9 \times 2 = 54.

Practice playeasy

A grain silo is shaped like a right circular cylinder with a radius of 44 feet and a height of 1010 feet. What is the volume of the silo, in cubic feet?

V=πr2h=π(4)2(10)=160πV = \pi r^{2} h = \pi (4)^{2}(10) = 160\pi cubic feet.

Practice playeasy

Find the volume of a sphere with radius 22. Use π=3\pi = 3.

V=43πr3=43×3×8=32V = \dfrac{4}{3} \pi r^{3} = \dfrac{4}{3} \times 3 \times 8 = 32.

Practice playeasy

A culvert pipe is a right circular cylinder with an inside diameter of 1212 inches and a length of 2020 inches. What is the volume of the pipe's interior, in cubic inches?

The radius is 66 inches. V=πr2h=π(6)2(20)=720πV = \pi r^{2} h = \pi (6)^{2}(20) = 720\pi cubic inches.

Practice playeasy

Find the volume of a cone with radius 22 and height 99. Use π=3\pi = 3.

V=13πr2h=13×3×4×9=36V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3} \times 3 \times 4 \times 9 = 36.

Practice playeasy

A community pool is a rectangular prism 2424 feet long, 1818 feet wide, and 66 feet deep when filled to the planned level. How many cubic feet of water does the pool hold at that level?

V=wh=24×18×6=2,592V = \ell w h = 24 \times 18 \times 6 = 2{,}592 cubic feet.

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