ATLAS Grade 8 The Number System. Practice it free.

$x = \sqrt{121} = 11$ because $11 \times 11 = 121$.

$6^2 = 36 < 40 < 49 = 7^2$, so $\sqrt{40}$ is between $6$ and $7$; the smaller is $6$.

$9 \times 9 = 81$, so $\sqrt{81} = 9$.

$5^2 = 25 < 27 < 36 = 6^2$, so $\sqrt{27}$ is between $5$ and $6$; the larger is $6$.

$10 \times 10 \times 10 = 1{,}000$, so $\sqrt[3]{1{,}000} = 10$.

$11^2 = 121$ sits right above $120$ and $\sqrt{120} \approx 10.95$, so the closest integer is $11$.

$8 \times 8 = 64$, so $\sqrt{64} = 8$.

$\sqrt{10} \approx 3.16$, so $\sqrt{10} + 2 \approx 5.16$; the integer part is $5$.