Irrational number approximations practice

$5^2 = 25 < 27 < 36 = 6^2$, so $\sqrt{27}$ is between $5$ and $6$; the larger is $6$.

$11^2 = 121$ sits right above $120$ and $\sqrt{120} \approx 10.95$, so the closest integer is $11$.

$\sqrt{10} \approx 3.16$, so $\sqrt{10} + 2 \approx 5.16$; the integer part is $5$.

$\pi \approx 3.14159$.

$\sqrt{2} \approx 1.414$.

$\sqrt{3} \approx 1.732$.

$\sqrt{5} \approx 2.236$.

$6^2 = 36 < 40 < 49 = 7^2$, so $\sqrt{40}$ is between $6$ and $7$; the smaller is $6$.