FAST Algebra 1 EOC Fractional Reasoning Practice

Fractional Reasoning skills

MA.912.FR.1.1, MA.912.FR.1.2, MA.912.FR.2.1, MA.912.FR.2.2, MA.912.FR.2.3

Standards basis

Florida B.E.S.T. Standards — Florida

How the FAST reports it

Florida’s FAST Mathematics is a state-specific assessment program aligned to the Florida B.E.S.T. Standards rather than a national framework. The published blueprint organizes results by reporting categories derived from B.E.S.T. domains, with separate blueprints for grades 3-8 FAST Mathematics and the B.E.S.T. Algebra 1 and Geometry EOCs.

Blueprint & weighting

Florida publishes blueprint percentage ranges by reporting category. The 2025-26 fact sheet states each PM event is tied to a blueprint for the full grade-level content, and the test design summary gives approximate item ranges per reporting category; the reporting-category statements note that a minimum of 15% of raw score points should come from each reporting category, with some domains combined when needed.

Official sources

Florida Department of Education FAST Assessments page
Florida Department of Education B.E.S.T. Mathematics Reporting Category Statements
Florida Department of Education B.E.S.T. Mathematics Test Design Summary

8 free questions · 0/0 correct

Practice playmedium

Given $f(x)=x^{3}-5$ , which of the following is $f^{-1}(x)$ ?

Set $y=x^{3}-5$ . Swap: $x=y^{3}-5$ . Add $5$ : $x+5=y^{3}$ . Take the cube root: $y=\sqrt[3]{x+5}$ . So $f^{-1}(x)=\sqrt[3]{x+5}\textsf{.}$

Practice playeasy

If $f(x) = 4x + 12\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = 4x + 12\textsf{.}$ Swap $x$ and $y\textsf{:}$ $x = 4y + 12\textsf{.}$ Subtract $12$ and divide by $4\textsf{:}$ $y = \dfrac{x - 12}{4}\textsf{.}$ So $f^{-1}(x) = \dfrac{x - 12}{4}\textsf{.}$

Practice playeasy

If $f(x) = \dfrac{x}{2} - 5\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = \dfrac{x}{2} - 5\textsf{.}$ Swap: $x = \dfrac{y}{2} - 5\textsf{.}$ Add $5$ and multiply by $2\textsf{:}$ $y = 2x + 10\textsf{.}$ So $f^{-1}(x) = 2x + 10\textsf{.}$

Practice playeasy

If $f(x) = 1 - 3x\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = 1 - 3x\textsf{.}$ Swap: $x = 1 - 3y\textsf{.}$ Then $3y = 1 - x\textsf{,}$ so $y = \dfrac{1 - x}{3}\textsf{.}$ So $f^{-1}(x) = \dfrac{1 - x}{3}\textsf{.}$

Practice playeasy

If $f(x) = \dfrac{2x + 6}{5}\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = \dfrac{2x + 6}{5}\textsf{.}$ Swap: $x = \dfrac{2y + 6}{5}\textsf{.}$ Multiply by $5\textsf{,}$ subtract $6\textsf{,}$ and divide by $2\textsf{:}$ $y = \dfrac{5x - 6}{2}\textsf{.}$ So $f^{-1}(x) = \dfrac{5x - 6}{2}\textsf{.}$

Practice playeasy

If $f(x) = 5x - 1\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = 5x - 1\textsf{.}$ Swap: $x = 5y - 1\textsf{.}$ Add $1$ and divide by $5\textsf{:}$ $y = \dfrac{x + 1}{5}\textsf{.}$ So $f^{-1}(x) = \dfrac{x + 1}{5}\textsf{.}$

Practice playeasy

If $f(x) = \dfrac{x - 4}{3}\textsf{,}$ which equation is $f^{-1}(x)\textsf{?}$

Set $y = \dfrac{x - 4}{3}\textsf{.}$ Swap: $x = \dfrac{y - 4}{3}\textsf{.}$ Multiply by $3$ and add $4\textsf{:}$ $y = 3x + 4\textsf{.}$ So $f^{-1}(x) = 3x + 4\textsf{.}$