FAST Grade 7 Geometric Reasoning and Measurement Practice

What the test measures

Geometric Reasoning and Measurement skills

7.GR.1.1, 7.GR.1.2, 7.GR.1.3
7.M.1.1, 7.M.1.2, 7.M.2.1, 7.M.2.2, 7.M.2.3

Standards basis

Florida B.E.S.T. Standards — Florida

How the FAST reports it

Florida’s FAST Mathematics is a state-specific assessment program aligned to the Florida B.E.S.T. Standards rather than a national framework. The published blueprint organizes results by reporting categories derived from B.E.S.T. domains, with separate blueprints for grades 3-8 FAST Mathematics and the B.E.S.T. Algebra 1 and Geometry EOCs.

Blueprint & weighting

Florida publishes blueprint percentage ranges by reporting category. The 2025-26 fact sheet states each PM event is tied to a blueprint for the full grade-level content, and the test design summary gives approximate item ranges per reporting category; the reporting-category statements note that a minimum of 15% of raw score points should come from each reporting category, with some domains combined when needed.

Official sources

Florida Department of Education FAST Assessments page
Florida Department of Education B.E.S.T. Mathematics Reporting Category Statements
Florida Department of Education B.E.S.T. Mathematics Test Design Summary

Practice by skill

Topics mapped to this domain

Try it now

8 free questions · 0/0 correct

Practice playeasy

Find the volume of a cone with radius $2$ and height $9$ . Use $\pi = 3$ .

$V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3} \times 3 \times 4 \times 9 = 36$ .

Practice playeasy

A cylinder has radius $2$ and height $4$ . Using $\pi = 3$ , what is its volume?

$V = \pi r^2 h = 3 \times 4 \times 4 = 48$ .

Practice playeasy

Parallelograms $EFGH$ and $JKLM$ are similar. The area of parallelogram $EFGH$ is $9\textsf{,}$ and the area of parallelogram $JKLM$ is $36\textsf{.}$ Side $EF$ corresponds to side $JK\textsf{,}$ and $EF = 7\textsf{.}$ What is the length of $JK\textsf{?}$

The area ratio is $\dfrac{36}{9} = 4 = k^{2}\textsf{,}$ so $k = 2\textsf{.}$ Then $JK = 7 \cdot 2 = 14\textsf{.}$

Practice playhard

A rectangular prism has volume $160$ cubic inches and height $5$ inches. The length is twice the width. What is the length, in inches?

$V = \ell w h$ and $\ell = 2w$ , so $160 = (2w)(w)(5) = 10w^2$ . Then $w^2 = 16$ , so $w = 4$ and $\ell = 8\text{ in}\textsf{.}$

Practice playhard

A rectangular pyramid tent has a $10$ -foot-by- $4$ -foot rectangular base. The two triangular faces along the $10$ -foot sides each have slant height $6$ feet, and the two triangular faces along the $4$ -foot sides each have slant height $5$ feet. The tent has no floor. What is the exterior surface area, in square feet, of the tent fabric?

Without a floor, only the four triangular faces are counted. Along the $10$ -foot sides: $2 \times \dfrac{1}{2}(10)(6) = 60$ . Along the $4$ -foot sides: $2 \times \dfrac{1}{2}(4)(5) = 20$ . The total is $60 + 20 = 80$ square feet.