ISAT Grade 11 Functions. Practice it free.

Interprets, builds, and compares functions in multiple representations. This Grade 11 reporting domain maps to 15 practice skills and 8 representative questions from the playable bank.

Grade 1115 mapped skills
What the test measures

Functions skills

  1. Interpret functions that arise in applications in terms of the context

  2. Build a function that models a relationship between two quantities

  3. Analyze functions using different representations

  4. Construct and compare linear, quadratic, and exponential models

Standards basis

Idaho Content Standards (Mathematics) — Idaho

How the ISAT reports it

Idaho ISAT is a state assessment administered to grades 3–8 and 11 and reported against Idaho grade-level content standards rather than a separate national testing framework. The public ISAT page points to summative blueprints and math specifications, while the Idaho Content Standards page shows the math program is organized by grade-band/domain progressions aligned to Idaho standards.

Blueprint & weighting

The public Idaho ISAT page references summative blueprints and item specifications, but the accessible official page content did not expose a published domain-by-domain percentage blueprint for math.

Try it now

8 free questions · 0/0 correct

Practice playmedium

The first five terms of an arithmetic sequence are 25,22,19,16,1325, 22, 19, 16, 13. What is the 1515th term?

The common difference is d=3d = -3. With a1=25a_1 = 25, the 1515th term is a15=25+14(3)=17a_{15} = 25 + 14(-3) = -17.

Practice playeasy

The function SS is defined by S(t)=450(0.85)t/3S(t) = 450(0.85)^{t/3}. The function SS models the height, in centimeters, of a snowpack, where tt is the number of days after a winter storm. According to the model, what is the estimated height, in centimeters, of the snowpack 33 days after the storm?

When t=3t = 3, the exponent is 3/3=13/3 = 1. So S(3)=450(0.85)1=382.5S(3) = 450(0.85)^1 = 382.5 centimeters.

Practice playeasy

A substance has a half-life of 11 years. What fraction remains after 22 years?

2÷1=22 \div 1 = 2 half-lives. Remaining: (12)2=14\left(\dfrac{1}{2}\right)^{2} = \dfrac{1}{4}.

Practice playeasy

For what value of xx does the graph of f(x)=6(x+9)(x13)f(x) = 6(x + 9)(x - 13) meet the xx-axis?

Set f(x)=0f(x) = 0: 6(x+9)(x13)=06(x + 9)(x - 13) = 0. The constant 606 \neq 0, so the zeros are x=9x = -9 and x=13x = 13. Of the choices, 9-9 is an x-coordinate of an x-intercept.

Practice playmedium

The table defines functions for positive integers x5x \leq 5.
xm(x)n(x)k(x)15242341313544525213\begin{array}{c|c|c|c} x & m(x) & n(x) & k(x) \\ \hline 1 & 5 & 2 & 4 \\ 2 & 3 & 4 & 1 \\ 3 & 1 & 3 & 5 \\ 4 & 4 & 5 & 2 \\ 5 & 2 & 1 & 3 \end{array}
If
m(n(k(x)))=1m(n(k(x))) = 1, what is the value of xx?

Work from the outside in. Since m(3)=1m(3) = 1, we need n(k(x))=3n(k(x)) = 3. Since n(3)=3n(3) = 3, we need k(x)=3k(x) = 3. From the table, k(5)=3k(5) = 3, so x=5x = 5.

Practice playeasy

The first term of a sequence is 1010. Each term after the first is 22 times the preceding term. If ana_n represents the nnth term, which equation gives ana_n in terms of nn?

Following the pattern:
1st term, or
n=1:n = 1\textsf{:} 102010 \cdot 2^{0}
2nd term, or
n=2:n = 2\textsf{:} 102110 \cdot 2^{1}
3rd term, or
n=3:n = 3\textsf{:} 102210 \cdot 2^{2}
4th term, or
n=4:n = 4\textsf{:} 102310 \cdot 2^{3}
Since each term has an exponent that is
11 less than the term number, the nnth term is an=102n1a_n = 10 \cdot 2^{n-1}.

Practice playeasy

Tree height, in feet, after xx years:
xf(x)120228336444\begin{array}{c|c} x & f(x) \\ \hline 1 & 20 \\ 2 & 28 \\ 3 & 36 \\ 4 & 44 \end{array}
The height is
f(x)=mx+12.f(x)=mx+12\textsf{.} What is m?m\textsf{?}

Slope-intercept form is f(x)=mx+b.f(x) = mx + b\textsf{.} The height increases by 88 feet each year, so m=8.m = 8\textsf{.}

Practice playeasy

Plant height, in centimeters, after xx weeks:
x0123k(x)8111417\begin{array}{c|cccc} x & 0 & 1 & 2 & 3 \\ \hline k(x) & 8 & 11 & 14 & 17 \end{array}
Which of the following is
k(x)?k(x)\textsf{?}

The height increases by 33 centimeters each week, and the starting height is 88 centimeters. So k(x)=3x+8.k(x) = 3x + 8\textsf{.}

Keep practicing

Turn functions into game time.

The ISAT placement starts with this test's real coverage map and finds the right difficulty.