HSF.BF.A.2 math practice. Learn by doing.

HSF.BF.A.2 practice covers write arithmetic and geometric sequences both recursively and with an explicit formula, and use them to model situations. Work through 8 free questions with answers and explanations, then continue in the related math games.

Grade 9Grade 113 mapped skills
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8 free questions · 0/0 correct

Practice playeasy

The first five terms of an arithmetic sequence are 12,18,24,30,3612, 18, 24, 30, 36. What is the 1111th term?

The common difference is d=6d = 6. With a1=12a_1 = 12, the 1111th term is a11=12+10(6)=72a_{11} = 12 + 10(6) = 72.

Practice playeasy

Find the 44th term: a1=2a_1 = 2, d=5d = 5.

a4=2+3(5)=2+15=17a_4 = 2 + 3(5) = 2 + 15 = 17.

Practice playeasy

The first term of a sequence is 22. Each term after the first is 44 times the preceding term. If ana_n represents the nnth term, which equation gives ana_n in terms of nn?

Following the pattern:
1st term, or
n=1:n = 1\textsf{:} 2402 \cdot 4^{0}
2nd term, or
n=2:n = 2\textsf{:} 2412 \cdot 4^{1}
3rd term, or
n=3:n = 3\textsf{:} 2422 \cdot 4^{2}
4th term, or
n=4:n = 4\textsf{:} 2432 \cdot 4^{3}
Since each term has an exponent that is
11 less than the term number, the nnth term is an=24n1a_n = 2 \cdot 4^{n-1}.

Practice playeasy

The first five terms of an arithmetic sequence are 1,4,7,10,131, 4, 7, 10, 13. What is the 1616th term?

The common difference is d=3d = 3. With a1=1a_1 = 1, the 1616th term is a16=1+15(3)=46a_{16} = 1 + 15(3) = 46.

Practice playeasy

Find the sum: 3+6+123 + 6 + 12.

Geometric series with a1=3a_1 = 3, r=2r = 2, n=3n = 3. Sum =3+6+12=21= 3 + 6 + 12 = 21.

Practice playeasy

The first term of a sequence is 88. Each term after the first is 22 times the preceding term. If f(n)f(n) represents the nnth term, which equation gives f(n)f(n) in terms of nn?

Following the pattern:
1st term, or
n=1:n = 1\textsf{:} 8208 \cdot 2^{0}
2nd term, or
n=2:n = 2\textsf{:} 8218 \cdot 2^{1}
3rd term, or
n=3:n = 3\textsf{:} 8228 \cdot 2^{2}
4th term, or
n=4:n = 4\textsf{:} 8238 \cdot 2^{3}
Since each term has an exponent that is
11 less than the term number, the nnth term is f(n)=82n1f(n) = 8 \cdot 2^{n-1}.

Practice playeasy

The first five terms of an arithmetic sequence are 6,11,16,21,266, 11, 16, 21, 26. What is the 1313th term?

The common difference is d=5d = 5. With a1=6a_1 = 6, the 1313th term is a13=6+12(5)=66a_{13} = 6 + 12(5) = 66.

Practice playeasy

Find the 44th term: a1=5a_1 = 5, d=3d = 3.

a4=5+3(3)=14a_{4} = 5 + 3(3) = 14.

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