CMAS High school Functions. Practice it free.

Studies function notation, relationships, and transformations, and applies functions to model and compare quantities. This High school reporting domain maps to 31 practice skills and 8 representative questions from the playable bank.

High schoolFunctions31 mapped skills
What the test measures

Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

  4. Build a function that models a relationship between two quantities

  5. Build new functions from existing functions

  6. Construct and compare linear, quadratic, and exponential models and solve problems

Standards basis

Colorado Academic Standards (mathematics) — Colorado

How the CMAS reports it

CMAS is Colorado’s statewide summative assessment system aligned to the Colorado Academic Standards rather than a national framework like SBAC or NAEP. The official CMAS page and Colorado standards materials indicate the math assessment is built from Colorado Academic Standards, but the retrieved official CMAS page did not expose a separate math blueprint document.

Blueprint & weighting

No official CMAS math domain weighting/percent-of-items blueprint was available in the retrieved primary CMAS materials.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The first five terms of an arithmetic sequence are 2,6,10,14,182, 6, 10, 14, 18. What is the 1717th term?

The common difference is d=4d = 4. With a1=2a_1 = 2, the 1717th term is a17=2+16(4)=66a_{17} = 2 + 16(4) = 66.

Practice playeasy

The function ff is defined by f(x)=x2−10f(x) = x^{2} - 10. What is the value of f(x)f(x) when x=6x = 6?

Substitute x=6x = 6: f(6)=62−10=36−10=26f(6) = 6^{2} - 10 = 36 - 10 = 26.

Practice playeasy

The function ff is defined by f(x)=x+5f(x) = \sqrt{x + 5}. What is the value of f(x)f(x) when x=11x = 11?

Substitute x=11x = 11: f(11)=11+5=16=4f(11) = \sqrt{11 + 5} = \sqrt{16} = 4.

Practice playeasy

For the function ff, f(0)=160f(0) = 160. For each increase in xx by 11, the value of f(x)f(x) decreases by 50%50\%. What is the value of f(3)f(3)?

A decrease of 50%50\% multiplies by 0.500.50 each step. So f(3)=160⋅0.503=160⋅0.125=20f(3) = 160 \cdot 0.50^3 = 160 \cdot 0.125 = 20.

Practice playeasy

b=100−4hb = 100 - 4h

The equation shown gives the estimated battery charge
b,b\textsf{,} as a percent, remaining on a laptop after hh hours of use, where 0≤h≤20.0 \le h \le 20\textsf{.} What is the estimated battery charge, as a percent, remaining on the laptop after 1212 hours of use?

Substitute h=12:h = 12\textsf{:} b=100−4(12)=100−48=52.b = 100 - 4(12) = 100 - 48 = 52\textsf{.} The estimated charge remaining is 5252 percent.

Practice playeasy

What is the value of log⁡232?\log_{2}32\textsf{?}

25=32,2^{5} = 32\textsf{,} so log⁡232=5.\log_{2}32 = 5\textsf{.}

Practice playeasy

An account starts with $500\text{\char36}500 and earns 20%20\% interest compounded yearly.

Choose the function model that correctly calculates the amount in the account after
33 years.

The amount after tt years is A(t)=P(1+r)t.A(t) = P(1 + r)^{t}\textsf{.} Here P=500,P = 500\textsf{,} r=0.20,r = 0.20\textsf{,} and t=3,t = 3\textsf{,} so A(3)=500(1.20)3=864.A(3) = 500(1.20)^{3} = 864\textsf{.}

Practice playeasy

The function LL is defined by L(w)=180(0.88)w/2L(w) = 180(0.88)^{w/2}. The function LL models the light output, in lumens, from a bulb, where ww is the number of weeks the bulb has been in use. According to the model, what is the estimated light output, in lumens, after 22 weeks of use?

When w=2w = 2, the exponent is 2/2=12/2 = 1. So L(2)=180(0.88)1=158.4L(2) = 180(0.88)^1 = 158.4 lumens.

Keep practicing

Turn functions into game time.

The CMAS placement starts with this test's real coverage map and finds the right difficulty.