HSF.BF.B.5 math practice. Learn by doing.

HSF.BF.B.5 practice covers understand the inverse relationship between exponents and logarithms and use this relationship to solve problems involving logarithms and exponents. Work through 8 free questions with answers and explanations, then continue in the related math games.

Grade 111 mapped skills
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Skills aligned to HSF.BF.B.5

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8 free questions · 0/0 correct

Practice playeasy

Simplify: log⁡2(8)\log_{2}(8).

23=82^{3} = 8, so log⁡2(8)=3\log_{2}(8) = 3.

Practice playeasy

Which expression is equal to log⁡2+log⁡5?\log 2 + \log 5\textsf{?}

The product rule rewrites a sum of logs as a log of a product, so log⁡2+log⁡5=log⁡(2⋅5).\log 2 + \log 5 = \log(2\cdot 5)\textsf{.}

Practice playeasy

Which rule combines log⁡a+log⁡b\log a + \log b into a single logarithm?

log⁡a+log⁡b=log⁡(ab)\log a + \log b = \log(ab) is the product rule.

Practice playeasy

Simplify: log⁡5(25)\log_{5}(25).

52=255^{2} = 25, so log⁡5(25)=2\log_{5}(25) = 2.

Practice playeasy

Which expression is equal to log⁡(3⋅4)?\log(3\cdot 4)\textsf{?}

The product rule rewrites a log of a product as a sum of logs, so log⁡(3⋅4)=log⁡3+log⁡4.\log(3\cdot 4) = \log 3 + \log 4\textsf{.}

Practice playeasy

Which rule rewrites 3log⁡a3\log a as a single logarithm?

3log⁡a=log⁡(a3)3\log a = \log(a^{3}) is the power rule.

Practice playeasy

Simplify: log⁡2(16)\log_{2}(16).

24=162^{4} = 16, so log⁡2(16)=4\log_{2}(16) = 4.

Practice playeasy

Which expression is equal to 4log⁡3?4\log 3\textsf{?}

The power rule rewrites a coefficient on a log as an exponent on the argument, so 4log⁡3=log⁡(34).4\log 3 = \log(3^{4})\textsf{.}

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