HSF.BF.B.5 math practice. Learn by doing.

HSF.BF.B.5 practice covers understand the inverse relationship between exponents and logarithms and use this relationship to solve problems involving logarithms and exponents. Work through 8 free questions with answers and explanations, then continue in the related math games.

Grade 111 mapped skills
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Skills aligned to HSF.BF.B.5

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8 free questions · 0/0 correct

Practice playeasy

Simplify: log5(25)\log_{5}(25).

52=255^{2} = 25, so log5(25)=2\log_{5}(25) = 2.

Practice playeasy

Which rule combines loga+logb\log a + \log b into a single logarithm?

loga+logb=log(ab)\log a + \log b = \log(ab) is the product rule.

Practice playeasy

Simplify: log2(16)\log_{2}(16).

24=162^{4} = 16, so log2(16)=4\log_{2}(16) = 4.

Practice playeasy

Which rule rewrites 3loga3\log a as a single logarithm?

3loga=log(a3)3\log a = \log(a^{3}) is the power rule.

Practice playeasy

Simplify: log3(9)\log_{3}(9).

32=93^{2} = 9, so log3(9)=2\log_{3}(9) = 2.

Practice playeasy

Simplify: log3(27)\log_{3}(27).

33=273^{3} = 27, so log3(27)=3\log_{3}(27) = 3.

Practice playeasy

Simplify: log2(32)\log_{2}(32).

25=322^{5} = 32, so log2(32)=5\log_{2}(32) = 5.

Practice playeasy

Simplify: log10(1000)\log_{10}(1000).

103=100010^{3} = 1000, so log10(1000)=3\log_{10}(1000) = 3.

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