ATLAS Algebra II Functions. Practice it free.

Interprets, builds, and compares functions; models relationships with linear, quadratic, exponential, logarithmic, and trigonometric functions. This Algebra II reporting domain maps to 30 practice skills and 8 representative questions from the playable bank.

Algebra II30 mapped skills
What the test measures

Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

  4. Build new functions from existing functions

  5. Construct and compare linear, quadratic, and exponential models and solve problems

  6. Interpret expressions for functions in terms of the situation they model

Standards basis

Arkansas Academic Standards for Mathematics (CCSS-M–aligned / Arkansas-adopted math standards) — Arkansas

How the ATLAS reports it

Arkansas’s statewide assessment system is ATLAS, which the ADE page says began serving in spring 2024. The official public page does not publish a math blueprint there, so the most defensible coverage map is the Arkansas math standards structure that ATLAS is aligned to.

Blueprint & weighting

ATLAS uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=3x2+2f(x) = 3x^{2} + 2. What is the value of f(x)f(x) when x=2x = 2?

Substitute x=2x = 2: f(2)=3(2)2+2=3(4)+2=12+2=14f(2) = 3(2)^{2} + 2 = 3(4) + 2 = 12 + 2 = 14.

Practice playeasy

The function f(x)f(x) is defined by f(x)=−3x+20f(x) = -3x + 20. For what value of xx does f(x)=5f(x) = 5?

Set −3x+20=5-3x + 20 = 5. Then −3x=−15-3x = -15, so x=5x = 5.

Practice playeasy

For the function hh, h(0)=64h(0) = 64. For each increase in xx by 11, the value of h(x)h(x) decreases by 25%25\%. What is the value of h(2)h(2)?

Each step multiplies by 1−0.25=0.751 - 0.25 = 0.75. So h(2)=64⋅0.752=64⋅0.5625=36h(2) = 64 \cdot 0.75^2 = 64 \cdot 0.5625 = 36.

Practice playeasy

a=250+15wa = 250 + 15w

The equation shown gives the estimated balance
a,a\textsf{,} in dollars, in a savings account after ww weeks of deposits, where 0≤w≤20.0 \le w \le 20\textsf{.} What is the estimated balance, in dollars, in the savings account after 66 weeks of deposits?

Substitute w=6:w = 6\textsf{:} a=250+15(6)=250+90=340.a = 250 + 15(6) = 250 + 90 = 340\textsf{.} The estimated balance is 340340 dollars.

Practice playeasy

What is the value of log⁡216?\log_{2}16\textsf{?}

24=16,2^{4} = 16\textsf{,} so log⁡216=4.\log_{2}16 = 4\textsf{.}

Practice playeasy

An 8080-milligram sample of a radioactive isotope has a half-life of 44 years.

Choose the function model that correctly calculates the amount remaining after
1212 years.

The remaining amount after tt years is A(t)=80(12)th,A(t) = 80\left(\dfrac{1}{2}\right)^{\textstyle\frac{t}{h}}\textsf{,} where hh is the half-life. Here t=12t = 12 and h=4,h = 4\textsf{,} so A(12)=80(12)124=80(12)3=10.A(12) = 80\left(\dfrac{1}{2}\right)^{\textstyle\frac{12}{4}} = 80\left(\dfrac{1}{2}\right)^{3} = 10\textsf{.}

Practice playeasy

The function gg is defined by g(t)=840(0.5)t/4g(t) = 840(0.5)^{t/4}. The function gg models the mass, in milligrams, of a medicine in a patient's bloodstream, where tt is the number of hours after an injection. According to the model, what is the estimated mass, in milligrams, of the medicine at the time of the injection?

At the time of injection, t=0t = 0. So g(0)=840(0.5)0=840g(0) = 840(0.5)^0 = 840 milligrams.

Practice playeasy

You invest $100\text{\char36}100 at 10%10\% annual interest compounded yearly for 22 years. What is the total?

Year 1: 100×1.10=110100 \times 1.10 = 110. Year 2: 110×1.10=121110 \times 1.10 = 121.

Keep practicing

Turn functions into game time.

The ATLAS placement starts with this test's real coverage map and finds the right difficulty.