Evaluating functions in context. Game on.

Evaluating functions in context is a grade 9 math skill aligned to Common Core standard HSF.IF.A.2: use function notation, evaluate functions for inputs in their domains, and interpret statements that use function notation in terms of a context. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 evaluating functions in context problems our math games drill.

CCSS HSF.IF.A.210 questions in the bank
Kickoff

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Warm-upeasy

b=1004hb = 100 - 4h

The equation shown gives the estimated battery charge
b,b\textsf{,} as a percent, remaining on a laptop after hh hours of use, where 0h20.0 \le h \le 20\textsf{.} What is the estimated battery charge, as a percent, remaining on the laptop after 1212 hours of use?

Substitute h=12:h = 12\textsf{:} b=1004(12)=10048=52.b = 100 - 4(12) = 100 - 48 = 52\textsf{.} The estimated charge remaining is 5252 percent.

Mid-gameeasy

p=32040dp = 320 - 40d

The equation shown gives the estimated number of pages
pp left to read in a book after dd days of a reading plan, where 0d8.0 \le d \le 8\textsf{.} What is the estimated number of pages left to read after 55 days of the reading plan?

Substitute d=5:d = 5\textsf{:} p=32040(5)=320200=120.p = 320 - 40(5) = 320 - 200 = 120\textsf{.} The estimated number of pages left is 120.120\textsf{.}

Mid-gameeasy

s=18n2s = 18 - \dfrac{n}{2}

The equation shown gives the estimated snow depth
s,s\textsf{,} in inches, remaining on a trail nn days after a storm, where 0n24.0 \le n \le 24\textsf{.} What is the estimated snow depth, in inches, remaining on the trail 1010 days after the storm?

Substitute n=10:n = 10\textsf{:} s=18102=185=13.s = 18 - \dfrac{10}{2} = 18 - 5 = 13\textsf{.} The estimated snow depth remaining is 1313 inches.

Mid-gameeasy

a=250+15wa = 250 + 15w

The equation shown gives the estimated balance
a,a\textsf{,} in dollars, in a savings account after ww weeks of deposits, where 0w20.0 \le w \le 20\textsf{.} What is the estimated balance, in dollars, in the savings account after 66 weeks of deposits?

Substitute w=6:w = 6\textsf{:} a=250+15(6)=250+90=340.a = 250 + 15(6) = 250 + 90 = 340\textsf{.} The estimated balance is 340340 dollars.

Mid-gameeasy

r=1208sr = 120 - 8s

The equation shown gives the estimated number of raffle tickets
rr remaining after ss sales periods at a festival booth, where 0s15.0 \le s \le 15\textsf{.} What is the estimated number of raffle tickets remaining after 77 sales periods?

Substitute s=7:s = 7\textsf{:} r=1208(7)=12056=64.r = 120 - 8(7) = 120 - 56 = 64\textsf{.} The estimated number remaining is 64.64\textsf{.}

Mid-gameeasy

g=9m4g = 9 - \dfrac{m}{4}

The equation shown gives the estimated amount of paint
g,g\textsf{,} in gallons, remaining after covering mm square meters of wall, where 0m36.0 \le m \le 36\textsf{.} What is the estimated amount of paint, in gallons, remaining after covering 1212 square meters of wall?

Substitute m=12:m = 12\textsf{:} g=9124=93=6.g = 9 - \dfrac{12}{4} = 9 - 3 = 6\textsf{.} The estimated amount remaining is 66 gallons.

Mid-gameeasy

T=72+3cT = 72 + 3c

The equation shown gives the estimated oven temperature
T,T\textsf{,} in degrees Fahrenheit, after cc heating cycles during a warm-up, where 0c10.0 \le c \le 10\textsf{.} What is the estimated oven temperature, in degrees Fahrenheit, after 55 heating cycles?

Substitute c=5:c = 5\textsf{:} T=72+3(5)=72+15=87.T = 72 + 3(5) = 72 + 15 = 87\textsf{.} The estimated temperature is 8787 degrees Fahrenheit.

Buzzer beatereasy

f=20n2f = 20 - \dfrac{n}{2}

The equation shown gives the estimated amount of flour
f,f\textsf{,} in cups, remaining after baking nn cookies, where 0n40.0 \le n \le 40\textsf{.} What is the estimated amount of flour, in cups, remaining after baking 1212 cookies?

Substitute n=12:n = 12\textsf{:} f=20122=206=14.f = 20 - \dfrac{12}{2} = 20 - 6 = 14\textsf{.} The estimated amount remaining is 1414 cups.

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