ATLAS Algebra I Functions. Practice it free.

Interprets, compares, and models functions using multiple representations. This Algebra I reporting domain maps to 19 practice skills and 8 representative questions from the playable bank.

Algebra I19 mapped skills
What the test measures

Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

  4. Build a function that models a relationship between two quantities

  5. Construct and compare linear, quadratic, and exponential models and solve problems

Standards basis

Arkansas Academic Standards for Mathematics (CCSS-M–aligned / Arkansas-adopted math standards) — Arkansas

How the ATLAS reports it

Arkansas’s statewide assessment system is ATLAS, which the ADE page says began serving in spring 2024. The official public page does not publish a math blueprint there, so the most defensible coverage map is the Arkansas math standards structure that ATLAS is aligned to.

Blueprint & weighting

ATLAS uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=3x+22f(x) = -3x + 22. What is the value of f(x)f(x) when x=5x = 5?

Substitute x=5x = 5: f(5)=3(5)+22=15+22=7f(5) = -3(5) + 22 = -15 + 22 = 7.

Practice playeasy

The function ff is defined by f(x)=x2+3f(x) = x^2 + 3. What is the value of f(x)f(x) when x=4x = 4?

Substitute x=4x = 4: f(4)=42+3=16+3=19f(4) = 4^2 + 3 = 16 + 3 = 19.

Practice playeasy

For the function ff, f(0)=250f(0) = 250. For each increase in xx by 11, the value of f(x)f(x) decreases by 40%40\%. What is the value of f(2)f(2)?

Each step multiplies by 10.40=0.601 - 0.40 = 0.60. So f(2)=2500.602=2500.36=90f(2) = 250 \cdot 0.60^2 = 250 \cdot 0.36 = 90.

Practice playeasy

s=18n2s = 18 - \dfrac{n}{2}

The equation shown gives the estimated snow depth
s,s\textsf{,} in inches, remaining on a trail nn days after a storm, where 0n24.0 \le n \le 24\textsf{.} What is the estimated snow depth, in inches, remaining on the trail 1010 days after the storm?

Substitute n=10:n = 10\textsf{:} s=18102=185=13.s = 18 - \dfrac{10}{2} = 18 - 5 = 13\textsf{.} The estimated snow depth remaining is 1313 inches.

Practice playeasy

The function SS is defined by S(t)=450(0.85)t/3S(t) = 450(0.85)^{t/3}. The function SS models the height, in centimeters, of a snowpack, where tt is the number of days after a winter storm. According to the model, what is the estimated height, in centimeters, of the snowpack 33 days after the storm?

When t=3t = 3, the exponent is 3/3=13/3 = 1. So S(3)=450(0.85)1=382.5S(3) = 450(0.85)^1 = 382.5 centimeters.

Practice playeasy

A substance has a half-life of 11 years. What fraction remains after 22 years?

2÷1=22 \div 1 = 2 half-lives. Remaining: (12)2=14\left(\dfrac{1}{2}\right)^{2} = \dfrac{1}{4}.

Practice playeasy

For what value of xx does the graph of f(x)=6(x+9)(x13)f(x) = 6(x + 9)(x - 13) meet the xx-axis?

Set f(x)=0f(x) = 0: 6(x+9)(x13)=06(x + 9)(x - 13) = 0. The constant 606 \neq 0, so the zeros are x=9x = -9 and x=13x = 13. Of the choices, 9-9 is an x-coordinate of an x-intercept.

Practice playmedium

The function RR is defined by R(n)=6n+15R(n) = 6n + 15. The function models the cost, in dollars, of printing nn posters for a student club. Which of the following is the best interpretation of the statement "R(7)R(7) is equal to 5757" in this context?

Here nn is the number of posters printed and R(n)R(n) is the cost in dollars. So R(7)=57R(7) = 57 means that when 77 posters are printed, the cost is 5757 dollars.

Keep practicing

Turn functions into game time.

The ATLAS placement starts with this test's real coverage map and finds the right difficulty.