MO MAP Algebra I Functions. Practice it free.

Interprets, builds, and analyzes functions, especially linear, quadratic, and exponential models. This Algebra I reporting domain maps to 22 practice skills and 8 representative questions from the playable bank.

Algebra I22 mapped skills
What the test measures

Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

  4. Build a function that models a relationship between two quantities

  5. Construct and compare linear, quadratic, and exponential models and solve problems

Standards basis

Missouri Learning Standards (Mathematics K-5 and Mathematics 6-12; revised standards approved April 19, 2016) — Missouri

How the MO MAP reports it

Missouri’s MAP math is built from the Missouri Learning Standards and the state’s item specifications, not from a separate national testing framework. The standards are closely CCSS-aligned in structure, with grade-level and course-level domains used as the native reporting/coverage structure.

Blueprint & weighting

Missouri publishes grade-level and EOC blueprints, but the accessible official pages in this pass did not expose the domain-by-domain percentage tables. The assessment page states that item specifications organize expectations by domains/strands and that blueprints are available for grade-level and EOC assessments.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=x210f(x) = x^{2} - 10. What is the value of f(x)f(x) when x=6x = 6?

Substitute x=6x = 6: f(6)=6210=3610=26f(6) = 6^{2} - 10 = 36 - 10 = 26.

Practice playeasy

The function ff is defined by f(x)=x+5f(x) = \sqrt{x + 5}. What is the value of f(x)f(x) when x=11x = 11?

Substitute x=11x = 11: f(11)=11+5=16=4f(11) = \sqrt{11 + 5} = \sqrt{16} = 4.

Practice playeasy

For the function ff, f(0)=160f(0) = 160. For each increase in xx by 11, the value of f(x)f(x) decreases by 50%50\%. What is the value of f(3)f(3)?

A decrease of 50%50\% multiplies by 0.500.50 each step. So f(3)=1600.503=1600.125=20f(3) = 160 \cdot 0.50^3 = 160 \cdot 0.125 = 20.

Practice playeasy

b=1004hb = 100 - 4h

The equation shown gives the estimated battery charge
b,b\textsf{,} as a percent, remaining on a laptop after hh hours of use, where 0h20.0 \le h \le 20\textsf{.} What is the estimated battery charge, as a percent, remaining on the laptop after 1212 hours of use?

Substitute h=12:h = 12\textsf{:} b=1004(12)=10048=52.b = 100 - 4(12) = 100 - 48 = 52\textsf{.} The estimated charge remaining is 5252 percent.

Practice playeasy

The function LL is defined by L(w)=180(0.88)w/2L(w) = 180(0.88)^{w/2}. The function LL models the light output, in lumens, from a bulb, where ww is the number of weeks the bulb has been in use. According to the model, what is the estimated light output, in lumens, after 22 weeks of use?

When w=2w = 2, the exponent is 2/2=12/2 = 1. So L(2)=180(0.88)1=158.4L(2) = 180(0.88)^1 = 158.4 lumens.

Practice playeasy

A substance has a half-life of 55 years. What fraction remains after 1010 years?

10÷5=210 \div 5 = 2 half-lives. Remaining: (12)2=14\left(\dfrac{1}{2}\right)^{2} = \dfrac{1}{4}.

Practice playeasy

For which value of xx does the graph of y=(x+8)(x2)y = -(x + 8)(x - 2) meet the xx-axis?

Set y=0y = 0: (x+8)(x2)=0-(x + 8)(x - 2) = 0. The factor 1-1 is nonzero, so the zeros come from x+8=0x=8x + 8 = 0 \Rightarrow x = -8 and x2=0x=2x - 2 = 0 \Rightarrow x = 2. Of the choices, 8-8 is an x-coordinate of an x-intercept.

Practice playmedium

The function TT is defined by T(d)=4d+86T(d) = -4d + 86. The function models the outdoor temperature, in degrees Fahrenheit, dd days after a cold front arrives. The domain of the function is 0d100 \le d \le 10. Which of the following is the best interpretation of the statement "T(3)T(3) is equal to 7474" in this context?

In this model, dd is days after the cold front arrives and T(d)T(d) is the temperature in degrees Fahrenheit. So T(3)=74T(3) = 74 means that 33 days after the cold front arrives, the temperature is 7474 degrees Fahrenheit.

Keep practicing

Turn functions into game time.

The MO MAP placement starts with this test's real coverage map and finds the right difficulty.