MO MAP Algebra I Statistics and Probability. Practice it free.

Summarizes, interprets, and uses data to make inferences and evaluate models. This Algebra I reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Algebra I9 mapped skills
What the test measures

Statistics and Probability skills

  1. Summarize, represent, and interpret data on a single count or measurement variable

  2. Make inferences and justify conclusions from sample surveys, experiments, and observational studies

  3. Use probability to evaluate outcomes of decisions

Standards basis

Missouri Learning Standards (Mathematics K-5 and Mathematics 6-12; revised standards approved April 19, 2016) — Missouri

How the MO MAP reports it

Missouri’s MAP math is built from the Missouri Learning Standards and the state’s item specifications, not from a separate national testing framework. The standards are closely CCSS-aligned in structure, with grade-level and course-level domains used as the native reporting/coverage structure.

Blueprint & weighting

Missouri publishes grade-level and EOC blueprints, but the accessible official pages in this pass did not expose the domain-by-domain percentage tables. The assessment page states that item specifications organize expectations by domains/strands and that blueprints are available for grade-level and EOC assessments.

Try it now

8 free questions · 0/0 correct

Practice playmedium

A grocer surveyed 2525 customers selected at random and found that 1515 of them purchased at least one organic item. Based on the survey, which of the following is the best estimate of the number of customers out of 500500 who would purchase at least one organic item?

The sample proportion is 1525=35\dfrac{15}{25} = \dfrac{3}{5}. The best estimate for 500500 customers is 35×500=300\dfrac{3}{5} \times 500 = 300 customers.

Practice playeasy

A survey recorded the number of text messages sent per day. Which group has the greatest standard deviation?

Group A:
50,50,50,50,5050, 50, 50, 50, 50
Group B:
40,45,50,55,6040, 45, 50, 55, 60
Group C:
48,49,50,51,5248, 49, 50, 51, 52
Group D:
30,50,50,50,7030, 50, 50, 50, 70

Group D has mean 5050 with values 3030 and 7070 each 2020 away from the center while three values sit at the mean, giving a standard deviation of about 12.612.6. Groups B and C spread less; Group A has zero spread.

Practice playeasy

The practice times, in minutes, for five days are 18,18\textsf{,} 22,22\textsf{,} 30,30\textsf{,} 20,20\textsf{,} and 35.35\textsf{.} Which data set has the same mean?

The original mean is 18+22+30+20+355=25\dfrac{18 + 22 + 30 + 20 + 35}{5} = 25. The set 15,15\textsf{,} 20,20\textsf{,} 25,25\textsf{,} 30,30\textsf{,} 3535 also has mean 2525, so the means match.

Practice playeasy

Five quiz scores are 92,92\textsf{,} 68,68\textsf{,} 75,75\textsf{,} 88,88\textsf{,} and 77.77\textsf{.} Which data set has the same median?

In order, the original values have middle value 7777, so the median is 7777. The set 70,70\textsf{,} 73,73\textsf{,} 77,77\textsf{,} 91,91\textsf{,} 9797 also has median 7777, so the medians match.

Practice playeasy

During a fitness challenge, four teammates completed 1515, 2020, 1818, and 2222 push-ups in the first four rounds. In the fifth round, one teammate completed xx push-ups. The mean number of push-ups per round is 1919. What is the value of xx?

Five rounds with a mean of 1919 push-ups total 5×19=955 \times 19 = 95. Since 15+20+18+22=7515 + 20 + 18 + 22 = 75, x=9575=20x = 95 - 75 = 20.

Practice playeasy

A box plot summarizes the data 1, 3, 3, 5, 8, 8, 10, 12. Find the median.

Order the data; the middle value is 6.56.5.

Practice playeasy

A science lab uses a random molecule selector. A fixed-width release bar is divided into 44 chamber gates that should release molecules equally often. After 500500 selections, the counts were:

| Chamber | Selections |
| :-- | --: |
| A |
128128 |
| B |
8282 |
| C |
127127 |
| D |
163163 |

Which change would most likely make the selector fair?

Four equal gates should each release about 5004=125\dfrac{500}{4}=125 times (25%25\%). Chamber B was selected only 8282 times (16.4%16.4\%), so its gate is too narrow, and chamber D was selected 163163 times (32.6%32.6\%), so its gate is too wide. Widening the gate for chamber B by narrowing the gate for chamber D shifts release space from the over-used chamber to the under-used one on the shared release bar.

Practice playeasy

Quiz scores are approximately normally distributed with mean 8080 and standard deviation 44. By the empirical rule, about what percent of scores are between 7272 and 8888? (Enter the number of percent.)

7272 and 8888 are each 2×4=82 \times 4 = 8 points, or 2 standard deviations, from the mean 8080, so by the empirical rule about 95%95\% of scores fall between them.

Keep practicing

Turn statistics and probability into game time.

The MO MAP placement starts with this test's real coverage map and finds the right difficulty.