ISAT Grade 6 Expressions and Equations. Practice it free.

The constants $10$ and $-4$ are like terms: $10 - 4 = 6$. The term $t^{2}$ stays the same, so the expression is equivalent to $t^{2} + 6\textsf{.}$

Combine: $-3x + 5x = 2x$, $-10 + 2 = -8$. Result: $2x - 8$.

$2^{5} = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 32\textsf{.}$

The base $2$ appears $5$ times as a factor, so $2 \times 2 \times 2 \times 2 \times 2 = 2^{5}$.

Multiply first: $5 \cdot 4 = 20$. Then $9 + 20 - 4 = 25$.

$\,1^3 = 1 \cdot 1 \cdot 1 = 1$.

The constants $15$ and $-7$ are like terms: $15 - 7 = 8$. The term $r^{2}$ stays the same, so the expression is equivalent to $r^{2} + 8\textsf{.}$

Distribute 5: $5 \cdot 9x + 5 \cdot -5 = 45x - 25$.