ISAT Grade 8 Geometry. Practice it free.

Applies similarity, transformations, and the Pythagorean Theorem. This Grade 8 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 89 mapped skills
What the test measures

Geometry skills

  1. Understand congruence and similarity using physical models, transparencies, or geometry software

  2. Understand and apply the Pythagorean Theorem

  3. Solve real-world and mathematical problems involving volume of cylinders, cones, and spheres

Standards basis

Idaho Content Standards (Mathematics) — Idaho

How the ISAT reports it

Idaho ISAT is a state assessment administered to grades 3–8 and 11 and reported against Idaho grade-level content standards rather than a separate national testing framework. The public ISAT page points to summative blueprints and math specifications, while the Idaho Content Standards page shows the math program is organized by grade-band/domain progressions aligned to Idaho standards.

Blueprint & weighting

The public Idaho ISAT page references summative blueprints and item specifications, but the accessible official page content did not expose a published domain-by-domain percentage blueprint for math.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius 11 and height 55. Using π=3\pi = 3, what is its volume?

V=πr2h=3×1×5=15V = \pi r^2 h = 3 \times 1 \times 5 = 15.

Practice playeasy

What is the distance from (1,2)(1, 2) to (4,6)(4, 6)?

Δx=3\Delta x = 3, Δy=4\Delta y = 4. 32+42=9+16=25=5\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Practice playeasy

In PQR\triangle PQR, P\angle P and Q\angle Q are congruent. The measure of R\angle R is 118.6118.6^{\circ}. What is the measure of Q\angle Q?

Let each congruent angle measure xx^{\circ}. Then 2x+118.6=1802x + 118.6 = 180, so x=180118.62=30.7x = \dfrac{180 - 118.6}{2} = 30.7^{\circ}.

Practice playeasy

What is the sum of the interior angles of a octagon?

A octagon has 88 sides: (82)×180=1080°(8-2) \times 180 = 1080°.

Practice playmedium

The shorter leg of a right triangle is 1111 centimeters and the longer leg is 6060 centimeters. What is the length of the hypotenuse?

The legs are 1111 and 6060. By the Pythagorean theorem, 112+602=121+3,600=3,72111^{2} + 60^{2} = 121 + 3{,}600 = 3{,}721, so the hypotenuse is 3,721=61\sqrt{3{,}721} = 61.

Practice playeasy

The hypotenuse of a right triangle is 2525, and one leg is 77. Find the other leg.

25272=62549=57625^{2} - 7^{2} = 625 - 49 = 576, so the other leg is 576=24.\sqrt{576} = 24\textsf{.}

Practice playeasy

A kite string is 2525 meters long and is staked 77 meters from a point on the ground directly below the kite. How high is the kite?

The string is the hypotenuse: 25272=62549=57625^{2} - 7^{2} = 625 - 49 = 576, so the height is 576=24\sqrt{576} = 24 meters.

Practice playhard

A rectangle has length 88 centimeters and area 120120 square centimeters. What is the length of a diagonal of the rectangle, in centimeters?

Area A=wA = \ell w, so 120=8w120 = 8w and w=15w = 15. The diagonal is the hypotenuse of a right triangle with legs 88 and 1515: 82+152=64+225=289=17 cm.\sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17\text{ cm}\textsf{.}

Keep practicing

Turn geometry into game time.

The ISAT placement starts with this test's real coverage map and finds the right difficulty.