KSA Grade 7 Statistics and Probability. Practice it free.

Use random sampling to draw inferences about a population; draw informal comparative inferences about two populations; and investigate chance processes and develop, use, and evaluate probability models. This Grade 7 reporting domain maps to 7 practice skills and 8 representative questions from the playable bank.

Grade 7SP7 mapped skills
What the test measures

Statistics and Probability skills

  1. Use random sampling to draw inferences about a population

  2. Draw informal comparative inferences about two populations

  3. Investigate chance processes and develop probability models

  4. Find probabilities of compound events using organized lists, tables, tree diagrams, and simulation

Standards basis

Kentucky Academic Standards (KAS) for Mathematics — Kentucky

How the KSA reports it

Kentucky KSA is a state summative assessment built on Kentucky Academic Standards (KAS) rather than a separate national framework. For mathematics, the assessed content closely follows Common Core–style grade-band domains in grades 3-8 and uses Kentucky high-school conceptual categories in grade 10.

Blueprint & weighting

KSA uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

Mia can pick from 55 shirts and 22 hats. How many different (shirt, hat) outfits are possible?

By the counting principle: 5×2=105 \times 2 = 10.

Practice playeasy

A jar contains 55 red tokens and 77 blue tokens. One token is chosen at random. What is the probability that the token is red?

There are 5+7=125 + 7 = 12 tokens in all and 55 are red, so P(red)=512P(\text{red}) = \dfrac{5}{12}.

Practice playeasy

One letter is chosen at random from the word GAMES. What is the probability the letter is a vowel?

GAMES has 55 letters, and 22 of them (AA and EE) are vowels, so P=25P = \dfrac{2}{5}.

Practice playeasy

The whole numbers 11 through 2424 were each written on separate cards. Those 2424 cards were placed in a bag. One card will be randomly drawn from this bag. What is the probability that the card will show a number divisible by 44?

Multiples of 44 from 11 to 2424 are 4,8,12,16,20,244, 8, 12, 16, 20, 24, so there are 66 favorable outcomes: P=624=14P = \tfrac{6}{24} = \tfrac{1}{4}.

Practice playeasy

A bag holds 44 red marbles and 55 green marbles. One marble is drawn at random. What is the probability it is green? Give a simplified fraction.

There are 4+5=94 + 5 = 9 marbles in all and 55 are green, so P(green)=59P(\text{green}) = \dfrac{5}{9}.

Practice playeasy

In a random sample of 40, 12 were red marbles. Estimate how many of 200 are red in the whole population.

Proportion =1240= \dfrac{12}{40}. Estimate =1240×200=60= \dfrac{12}{40} \times 200 = 60.

Practice playeasy

Spinner A has 55 equal sections and exactly 11 section is gold. Spinner B has 44 equal sections and exactly 11 section is gold. Each spinner is spun once. What is the probability that both spinners land on gold?

P(gold on A)=15P(\text{gold on A}) = \dfrac{1}{5} and P(gold on B)=14P(\text{gold on B}) = \dfrac{1}{4}. So P(both gold)=15×14=120P(\text{both gold}) = \dfrac{1}{5} \times \dfrac{1}{4} = \dfrac{1}{20}.

Practice playeasy

For two independent events, the probability of a head then a 4: P(A)=12P(A)=\tfrac{1}{2}, P(B)=16P(B)=\tfrac{1}{6}. Find P(A and B)P(A \text{ and } B) as a simplified fraction.

Multiply: P(A and B)=12×16=112P(A \text{ and } B) = \tfrac{1}{2} \times \tfrac{1}{6} = \tfrac{1}{12}.

Keep practicing

Turn statistics and probability into game time.

The KSA placement starts with this test's real coverage map and finds the right difficulty.