KSA Grade 8 Geometry Practice — Sports Academy Games

What the test measures

Geometry skills

Verify experimentally the properties of rotations, reflections, and translations
Understand congruence in terms of rigid motions
Understand similarity in terms of similarity transformations
Use the Pythagorean Theorem to determine unknown side lengths in right triangles
Apply the Pythagorean Theorem to find distances in the coordinate plane
Solve real-world and mathematical problems involving volume of cylinders, cones, and spheres

Standards basis

Kentucky Academic Standards (KAS) for Mathematics — Kentucky

How the KSA reports it

Kentucky KSA is a state summative assessment built on Kentucky Academic Standards (KAS) rather than a separate national framework. For mathematics, the assessed content closely follows Common Core–style grade-band domains in grades 3-8 and uses Kentucky high-school conceptual categories in grade 10.

Blueprint & weighting

KSA uses the Independent / state-specific framework (by grade domains structure).

Official sources

Kentucky Department of Education — Kentucky Summative Assessment
Kentucky Department of Education — Mathematics
Kentucky Department of Education — Kentucky Laws and Regulations

Practice by skill

Topics mapped to this domain

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius $2$ and height $3$ . Using $\pi = 3$ , what is its volume?

$V = \pi r^2 h = 3 \times 4 \times 3 = 36$ .

Practice playeasy

The distance between $(0, 0)$ and $(6, 8)$ is $d$ . What is $d^{2}$ ?

$d^{2} = 6^2 + 8^2 = 36 + 64 = 100$ .

Practice playmedium

In a right triangle, one leg is $9$ feet and the hypotenuse is $41$ feet. How long is the other leg?

Let the missing leg be $x$ . Then $x^{2} + 9^{2} = 41^{2}$ , so $x^{2} = 41^{2} - 9^{2} = 1{,}681 - 81 = 1{,}600$ and $x = \sqrt{1{,}600} = 40$ .

Practice playeasy

One leg of a right triangle is $10$ and the hypotenuse is $26$ . What is the missing leg?

$26^{2} - 10^{2} = 676 - 100 = 576$ , so the missing leg is $\sqrt{576} = 24\textsf{.}$

Practice playeasy

A $26$ -meter guy wire runs from the top of a pole to a stake $24$ meters from the pole's base. How tall is the pole?

The wire is the hypotenuse: $26^{2} - 24^{2} = 676 - 576 = 100$ , so the pole is $\sqrt{100} = 10$ meters tall.

Practice playhard

A rectangle has length $8$ centimeters and area $120$ square centimeters. What is the length of a diagonal of the rectangle, in centimeters?

Area $A = \ell w$ , so $120 = 8w$ and $w = 15$ . The diagonal is the hypotenuse of a right triangle with legs $8$ and $15$ : $\sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17\text{ cm}\textsf{.}$