KSA Grade 8 Expressions and Equations. Practice it free.

$12 \times 12 = 144$, so $\sqrt{144} = 12$.

The Power of a Product Property says that a product raised to a power equals each factor raised to that power, written $(ab)^{n} = a^{n} \cdot b^{n}\textsf{.}$ Here $(3 \cdot 7)^{4} = 3^{4} \cdot 7^{4}$, so $a = 4\textsf{.}$

Both equations have slope $-3$ but different $y$-intercepts ($2$ and $5$), so the lines are parallel and the system has no solution.

Rewrite in slope-intercept form: $y = 2x - 3$ and $y = 2x - 3$. The slopes and $y$-intercepts match, so the equations describe the same line and the system has infinitely many solutions.

Subtract $2x$ from both sides: $3x + 4 = 19$. Subtract $4$ from both sides: $3x = 15$. Divide by $3$: $x = 5\textsf{.}$

Subtract $4$ from both sides: $5y - 4 = -2x$. Divide both sides by $-2$: $x = \dfrac{5y - 4}{-2} = \dfrac{-5y + 4}{2}$.

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = -14$, so the $y$-intercept is $(0, -14)\textsf{.}$

$5 \times 5 \times 5 = 125$, so $\sqrt[3]{125} = 5$.