Y-intercept as a point. Game on.

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = -5$, so the $y$-intercept is $(0, -5)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = -14$, so the $y$-intercept is $(0, -14)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = 27$, so the $y$-intercept is $(0, 27)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = 6$, so the $y$-intercept is $(0, 6)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = -19$, so the $y$-intercept is $(0, -19)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = -3$, so the $y$-intercept is $(0, -3)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = 4$, so the $y$-intercept is $(0, 4)\textsf{.}$

In $y = mx + b$, the $y$-intercept is the point $(0, b)$. Here $b = 22$, so the $y$-intercept is $(0, 22)\textsf{.}$