SBAC Grade 8 Concepts and Procedures. Practice it free.

Students can explain and apply mathematical concepts and interpret and carry out mathematical procedures with precision and fluency. Content is drawn from the Grade 8 clusters listed as targets below, with a much greater proportion from clusters the blueprint designates as priority (major) clusters. This Grade 8 reporting domain maps to 27 practice skills and 8 representative questions from the playable bank.

Grade 8Claim 127 mapped skills
What the test measures

Concepts and Procedures skills

  1. Target A: Know that there are numbers that are not rational, and approximate them by rational numbers

  2. Target B: Work with radicals and integer exponents

  3. Target C: Understand the connections between proportional relationships, lines, and linear equations

  4. Target D: Analyze and solve linear equations and pairs of simultaneous linear equations

  5. Target E: Define, evaluate, and compare functions

  6. Target F: Use functions to model relationships between quantities

  7. Target G: Understand congruence and similarity using physical models, transparencies, or geometry software

  8. Target H: Understand and apply the Pythagorean theorem

  9. Target I: Solve real-world and mathematical problems involving volume of cylinders, cones, and spheres

  10. Target J: Investigate patterns of association in bivariate data

Standards basis

Common Core State Standards for Mathematics (CCSS-M) — national

How the SBAC reports it

Smarter Balanced math is organized into four claims with published assessment targets (Mathematics Content Specifications). Claim 1 (Concepts and Procedures) publishes per-grade assessment targets for grades 3-8 and high school, each a verbatim CCSS-M cluster heading (e.g. grade 3 Target A is cluster 3.OA.A); Claims 2-4 are cross-cutting process claims whose targets are constant across grades and draw on the same grade-level content. On score reports, Claims 2 and 4 are combined into a single reporting category, so three claim scores accompany the overall math score.

Blueprint & weighting

Content Specifications (Reporting Categories section): the total mathematics score is a weighted composite of the four claims — Claim 1 (Concepts and Procedures) contributes roughly 50%, Claim 3 (Communicating Reasoning) roughly 25%, and combined Claims 2 and 4 (Problem Solving / Modeling and Data Analysis) about 25%. The summative blueprint (as of 2018-19) publishes item counts per test event rather than percentages: Claim 1 is 17-20 items in grades 3-5, 16-20 in grades 6-8, and 19-22 in grade 11; the Claim 2/4 and Claim 3 reporting categories are 8-10 items each, totaling 18-20 across the two.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius 11 and height 55. Using π=3\pi = 3, what is its volume?

V=πr2h=3×1×5=15V = \pi r^2 h = 3 \times 1 \times 5 = 15.

Practice playeasy

What is the yy-intercept of the graph of y=5x+27y = 5x + 27 in the coordinate plane?

In y=mx+by = mx + b, the yy-intercept is the point (0,b)(0, b). Here b=27b = 27, so the yy-intercept is (0,27).(0, 27)\textsf{.}

Practice playeasy

Which is closest to π\pi?

π≈3.14159\pi \approx 3.14159.

Practice playeasy

What is the slope of the line y=32x+2y = \dfrac{3}{2}x + 2?

In y=mx+by = mx + b, the slope is m=32m = \dfrac{3}{2}.

Practice playeasy

Which of the following systems of linear equations has no solution?

Both equations have slope 22 but different yy-intercepts (33 and −1-1), so the lines are parallel and the system has no solution.

Practice playeasy

In △PQR\triangle PQR, ∠P\angle P and ∠Q\angle Q are congruent. The measure of ∠R\angle R is 118.6∘118.6^{\circ}. What is the measure of ∠Q\angle Q?

Let each congruent angle measure x∘x^{\circ}. Then 2x+118.6=1802x + 118.6 = 180, so x=180−118.62=30.7∘x = \dfrac{180 - 118.6}{2} = 30.7^{\circ}.

Practice playeasy

{x+y=53x−y=3\begin{cases} x + y = 5 \\ 3x - y = 3 \end{cases}

How many solutions does the given system of equations have?

Rewrite in slope-intercept form: y=−x+5y = -x + 5 and y=3x−3y = 3x - 3. The slopes −1-1 and 33 are different, so the lines intersect at exactly one point.

Practice playmedium

Consider the linear function tt given by t(x)=nx+150t(x) = nx + 150, where nn is a constant. Knowing that t(10)=80t(10) = 80, determine t(20)t(20).

Substitute x=10x = 10: 10n+150=8010n + 150 = 80, so 10n=−7010n = -70 and n=−7n = -7. The rule is t(x)=−7x+150t(x) = -7x + 150, so t(20)=−7(20)+150=−140+150=10t(20) = -7(20) + 150 = -140 + 150 = 10.

Keep practicing

Turn concepts and procedures into game time.

The SBAC placement starts with this test's real coverage map and finds the right difficulty.