Evaluating exponential functions is a grade 8 math skill aligned to Common Core standard 8.EE.A.3: use numbers expressed in the form of a single digit times an integer power of 10 to estimate very large or very small quantities. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 evaluating exponential functions problems our math games drill.
CCSS 8.EE.A.310 questions in the bank
Sample questions
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Question 1medium
Let f(t)=8e3t+50. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(2)?
Substitute t=2: f(2)=8e6+50. Since e6≈403.4, f(2)≈8(403.4)+50=3,277≈3×103.
Question 2medium
Let f(t)=4e3t+200. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(3)?
Substitute t=3: f(3)=4e9+200. Since e9≈8,103, f(3)≈4(8,103)+200=32,612≈3×104.
Question 3medium
Let f(t)=4e2t+50. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(4)?
Substitute t=4: f(4)=4e8+50. Since e8≈2,981, f(4)≈4(2,981)+50=11,974≈1×104.
Question 4hard
Let f(t)=3e2t+10. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(5)?
Substitute t=5: f(5)=3e10+10. Since e10≈22,026, f(5)≈3(22,026)+10=66,088≈7×104.
Question 5hard
Let f(t)=6e2t. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(5)?
Substitute t=5: f(5)=6e10. Since e10≈22,026, f(5)≈6(22,026)=132,156≈1×105.
Question 6hard
Let f(t)=5e3t+200. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(4)?
Substitute t=4: f(4)=5e12+200. Since e12≈162,755, f(4)≈5(162,755)+200=813,975≈8×105.
Question 7hard
Let f(t)=2e3t+1,000. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(4)?
Substitute t=4: f(4)=2e12+1,000. Since e12≈162,755, f(4)≈2(162,755)+1,000=326,510≈3×105.
Question 8hard
Let f(t)=e3t. Which of the following approximations, written as a×10n with one significant digit, is closest to the value of f(5)?
Substitute t=5: f(5)=e15. Since e15≈3,269,017, f(5)≈3×106.
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