MAST Grade 7 Measures of Center and Variability. Practice it free.

Students make inferences about a population from sample data and compare populations using measures of center and variability. This Grade 7 reporting domain maps to 1 practice skill and 8 representative questions from the playable bank.

Grade 7Testlet 111 mapped skills
What the test measures

Measures of Center and Variability skills

  1. Make inferences about a population based on sample data.

  2. Use measures of center and variability to draw informal comparisons about two populations.

  3. Standards: 7.SP.1, 7.SP.2, 7.SP.3, 7.SP.4

Standards basis

Montana PK-12 Mathematics Content Standards / Common Core State Standards for Mathematics (CCSS-M)-aligned Montana standards — Montana

How the MAST reports it

Montana’s MAST is a state-specific through-year assessment built by New Meridian and aligned to Montana’s academic content standards, not a Smarter Balanced-style claims/targets framework. The math blueprints organize content into grade-level strands/testlets that map directly to CCSS-M-derived Montana standards.

Blueprint & weighting

The blueprint publishes a through-year design of 12 strands/testlets per grade, with 1 strand per testlet, 2 reporting attributes per strand, and 9–13 items per testlet. It also specifies approximate item-type and DOK distributions, but does not publish percentage weighting by domain in the captured blueprint text.

Practice by skill

Topics mapped to this domain

Try it now

8 free questions · 0/0 correct

Practice playeasy

In a random sample of 30, 9 were left-handed students. Estimate how many of 300 are left-handed in the whole population.

Proportion =930= \dfrac{9}{30}. Estimate =930×300=90= \dfrac{9}{30} \times 300 = 90.

Practice playeasy

In a random sample of 50, 15 were defective bulbs. Estimate how many of 400 are defective in the whole population.

Proportion =1550= \dfrac{15}{50}. Estimate =1550×400=120= \dfrac{15}{50} \times 400 = 120.

Practice playeasy

In a random sample of 20, 7 were voters favoring the plan. Estimate how many of 100 are favoring in the whole population.

Proportion =720= \dfrac{7}{20}. Estimate =720×100=35= \dfrac{7}{20} \times 100 = 35.

Practice playeasy

A random sample of 12 contained 3 successes. What is the sample proportion (as a simplified fraction)?

Proportion =312=14= \dfrac{3}{12} = \dfrac{1}{4}.

Practice playeasy

A random sample of 20 contained 5 successes. What is the sample proportion (as a simplified fraction)?

Proportion =520=14= \dfrac{5}{20} = \dfrac{1}{4}.

Practice playeasy

A random sample of 32 contained 8 successes. What is the sample proportion (as a simplified fraction)?

Proportion =832=14= \dfrac{8}{32} = \dfrac{1}{4}.

Practice playeasy

In a random sample, 12 of 48 shoppers chose vanilla. What percent of all shoppers would you expect to choose vanilla?

1248=14=25%\dfrac{12}{48} = \dfrac{1}{4} = 25\%.

Practice playeasy

In a random sample of 40, 12 were red marbles. Estimate how many of 200 are red in the whole population.

Proportion =1240= \dfrac{12}{40}. Estimate =1240×200=60= \dfrac{12}{40} \times 200 = 60.

Keep practicing

Turn measures of center and variability into game time.

The MAST placement starts with this test's real coverage map and finds the right difficulty.