MCAP Grade 8 Geometry. Practice it free.

Measures congruence and similarity, the Pythagorean Theorem, and volume of cylinders, cones, and spheres. This Grade 8 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 8Content Subclaim9 mapped skills
What the test measures

Geometry skills

  1. 8.G.A Understand congruence and similarity using physical models, transparencies, or geometry software.

  2. 8.G.B Understand and apply the Pythagorean Theorem.

  3. 8.G.C Solve real-world and mathematical problems involving volume of cylinders, cones, and spheres.

Standards basis

Maryland College and Career Ready Standards for Mathematics (MCCRSM) — Maryland

How the MCAP reports it

MCAP is Maryland's statewide successor to PARCC, built on the Maryland College and Career Ready Standards for Mathematics (which mirror CCSS-M) — it is not a Smarter Balanced administration despite the claims-style family resemblance. Each grade/course High Level Blueprint (September 2022) organizes the assessment into three subclaims: Content (23-24 one-point machine-scored items, listed per domain/conceptual category as MCCRSM cluster headings), Reasoning (6 items), and Modeling (6 items), the latter two defined by per-grade evidence statements and including constructed-response items. Cluster headings are transcribed verbatim from the blueprints, including their minor typographical deviations from the parallel CCSS-M headings; two evident misprints are normalized (a duplicated sentence fragment on 4.OA.C, and the domain codes printed as G.P.E / T.TF for G.GPE / F.TF). Since March 2025, grade 6-7 students enrolled in a high-school mathematics course may take the corresponding MCAP course assessment instead of the grade-level test.

Blueprint & weighting

Each High Level Blueprint (September 2022) publishes per-domain operational item counts. Content Subclaim (1-point machine-scored items): Grade 3 — OA 7, NBT 2, NF 7, Measurement 5, Geometry 2 (23 items); Grade 4 — OA 4, NBT 5, NF 10, Measurement 3, Geometry 1 (23); Grade 5 — OA 2, NBT 6, NF 9, Measurement 4, Geometry 2 (23); Grade 6 — RP 3, NS 8, EE 8, Geometry 2, SP 2 (23); Grade 7 — RP 8, NS 4, EE 5, Geometry 3, SP 3 (23); Grade 8 — NS 2, EE 10, Functions 5, Geometry 4, SP 2 (23); Algebra I — Number and Quantity 1, Algebra 12, Functions 9, Statistics 2 (24); Geometry — G.CO 7, G.SRT 8, G.C 3, G.GPE 3, G.GMD 1, G.MG 1 (23); Algebra II — Number and Quantity 3, Algebra 8, Functions 11, Statistics 1 (23). Every assessment adds 6 Reasoning Subclaim and 6 Modeling Subclaim operational items — four 1-point machine-scored each, plus two constructed-response items (two 3-point in grades 3-4; one 3-point and one 4-point in grades 5-8; two 4-point in Algebra I, Geometry, and Algebra II) — so a form carries 35 operational items (36 for Algebra I).

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius 11 and height 55. Using π=3\pi = 3, what is its volume?

V=πr2h=3×1×5=15V = \pi r^2 h = 3 \times 1 \times 5 = 15.

Practice playeasy

In PQR\triangle PQR, P\angle P and Q\angle Q are congruent. The measure of R\angle R is 118.6118.6^{\circ}. What is the measure of Q\angle Q?

Let each congruent angle measure xx^{\circ}. Then 2x+118.6=1802x + 118.6 = 180, so x=180118.62=30.7x = \dfrac{180 - 118.6}{2} = 30.7^{\circ}.

Practice playeasy

What is the sum of the interior angles of a octagon?

A octagon has 88 sides: (82)×180=1080°(8-2) \times 180 = 1080°.

Practice playeasy

In a triangle, mP=105m\angle P = 105^{\circ} and mQ=28.m\angle Q = 28^{\circ}\textsf{.} What is mR?m\angle R\textsf{?}

The sum of the interior angles of a triangle is 180.180^{\circ}\textsf{.} So mR=18010528=47.m\angle R = 180^{\circ} - 105^{\circ} - 28^{\circ} = 47^{\circ}\textsf{.}

Practice playeasy

What is the distance from (1,2)(1, 2) to (4,6)(4, 6)?

Δx=3\Delta x = 3, Δy=4\Delta y = 4. 32+42=9+16=25=5\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Practice playmedium

The shorter leg of a right triangle is 1111 centimeters and the longer leg is 6060 centimeters. What is the length of the hypotenuse?

The legs are 1111 and 6060. By the Pythagorean theorem, 112+602=121+3,600=3,72111^{2} + 60^{2} = 121 + 3{,}600 = 3{,}721, so the hypotenuse is 3,721=61\sqrt{3{,}721} = 61.

Practice playeasy

The hypotenuse of a right triangle is 2525, and one leg is 77. Find the other leg.

25272=62549=57625^{2} - 7^{2} = 625 - 49 = 576, so the other leg is 576=24.\sqrt{576} = 24\textsf{.}

Practice playeasy

A kite string is 2525 meters long and is staked 77 meters from a point on the ground directly below the kite. How high is the kite?

The string is the hypotenuse: 25272=62549=57625^{2} - 7^{2} = 625 - 49 = 576, so the height is 576=24\sqrt{576} = 24 meters.

Keep practicing

Turn geometry into game time.

The MCAP placement starts with this test's real coverage map and finds the right difficulty.