MCAS Grade 10 Functions. Practice it free.

Measures functions, their representations, and their use in modeling relationships. This Grade 10 reporting domain maps to 13 practice skills and 8 representative questions from the playable bank.

Grade 1013 mapped skills
What the test measures

Functions skills

  1. Understand the concept of a function

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

Standards basis

Massachusetts Curriculum Frameworks / Massachusetts learning standards (CCSS-aligned math standards as adopted by Massachusetts) — Massachusetts

How the MCAS reports it

MCAS is Massachusetts’ statewide assessment program, and its math design is built on Massachusetts Curriculum Frameworks rather than a separate multi-state framework. The official MCAS pages state that MCAS assessments are based on the state’s learning standards and that the math tests are organized by Massachusetts grade-band domains/reporting categories.

Blueprint & weighting

The official MCAS math blueprint/test-design materials were not successfully retrievable in this session, so published domain weightings could not be verified from a primary PDF/page.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=x2+4xf(x) = x^{2} + 4x. What is the value of f(x)f(x) when x=5x = 5?

Substitute x=5x = 5: f(5)=52+4(5)=25+20=45f(5) = 5^{2} + 4(5) = 25 + 20 = 45.

Practice playeasy

The function ff is defined by f(x)=x2+6f(x) = \dfrac{x}{2} + 6. What is the value of f(x)f(x) when x=4x = 4?

Substitute x=4x = 4: f(4)=42+6=2+6=8f(4) = \dfrac{4}{2} + 6 = 2 + 6 = 8.

Practice playeasy

For the function ff, f(0)=125f(0) = 125. For each increase in xx by 11, the value of f(x)f(x) increases by 20%20\%. What is the value of f(2)f(2)?

Each step multiplies by 1.201.20. So f(2)=125⋅1.202=125⋅1.44=180f(2) = 125 \cdot 1.20^2 = 125 \cdot 1.44 = 180.

Practice playeasy

T=72+3cT = 72 + 3c

The equation shown gives the estimated oven temperature
T,T\textsf{,} in degrees Fahrenheit, after cc heating cycles during a warm-up, where 0≤c≤10.0 \le c \le 10\textsf{.} What is the estimated oven temperature, in degrees Fahrenheit, after 55 heating cycles?

Substitute c=5:c = 5\textsf{:} T=72+3(5)=72+15=87.T = 72 + 3(5) = 72 + 15 = 87\textsf{.} The estimated temperature is 8787 degrees Fahrenheit.

Practice playeasy

For what value of xx does the graph of y=−5(x−11)(x+4)y = -5(x - 11)(x + 4) intercept the xx-axis?

Set y=0y = 0: −5(x−11)(x+4)=0-5(x - 11)(x + 4) = 0. The constant −5≠0-5 \neq 0, so the zeros are x=11x = 11 and x=−4x = -4. Of the choices, −4-4 is an x-coordinate of an x-intercept.

Practice playeasy

The equation of a line is 4x−5y=−120.4x - 5y = -120\textsf{.} What is the xx-intercept of the line?

The xx-intercept is the value of xx when y=0.y = 0\textsf{.} Substituting gives 4x=−120,4x = -120\textsf{,} so x=−30.x = -30\textsf{.}

Practice playmedium

The function BB is defined by B(y)=2,500(1.06)yB(y) = 2{,}500(1.06)^{y}. The function models the balance, in dollars, of a savings account yy years after it was opened. The domain of the function is 0≤y≤120 \le y \le 12. Which of the following is the best interpretation of the statement "B(4)B(4) is approximately equal to 3,1563{,}156" in this context?

Here yy is years after the account was opened and B(y)B(y) is the balance in dollars. So B(4)≈3,156B(4) \approx 3{,}156 means that about 44 years after the account was opened, the balance is approximately 3,1563{,}156 dollars.

Practice playeasy

The equation of a line is y−4=−3(x+3).y - 4 = -3(x + 3)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−3,4).(x_1, y_1) = (-3, 4)\textsf{.}

Keep practicing

Turn functions into game time.

The MCAS placement starts with this test's real coverage map and finds the right difficulty.