PARCC Algebra II The Complex Number System. Practice it free.

Students perform arithmetic operations with complex numbers and use complex numbers in polynomial identities and equations. This Algebra II reporting domain maps to 3 practice skills and 8 representative questions from the playable bank.

Algebra II3 mapped skills
What the test measures

The Complex Number System skills

  1. Perform arithmetic operations with complex numbers

  2. Use complex numbers in polynomial identities and equations

Standards basis

Common Core State Standards for Mathematics (CCSS-M) / PARCC Model Content Frameworks — national

How the PARCC reports it

PARCC was a multistate assessment system built around the Common Core-era PARCC mathematics model content frameworks rather than a separate proprietary standards set. Its math structure is organized by grade/course and aligned to CCSS-M content categories and model content frameworks.

Blueprint & weighting

No single published PARCC weighting table was located in the accessible sources used here.

Try it now

8 free questions · 0/0 correct

Practice playmedium

What is the value of (4+i)(3+2i)(4+i)(3+2i)?

Expand: (4+i)(3+2i)=12+8i+3i+2i2(4+i)(3+2i)=12+8i+3i+2i^{2}. Since i2=1i^{2}=-1, this is 12+11i2=10+11i.12+11i-2=10+11i\textsf{.}

Practice playeasy

What is 5+12i|5 + 12i|?

5+12i=52+122=169=13|5 + 12i| = \sqrt{5^2 + 12^2} = \sqrt{169} = 13.

Practice playmedium

Given i=1i = \sqrt{-1}, what is 4916\sqrt{49} - \sqrt{-16}?

49=7\sqrt{49} = 7 and 16=4i\sqrt{-16} = 4i. So 4916=74i\sqrt{49} - \sqrt{-16} = 7 - 4i.

Practice playmedium

(1+6i)(16i)(1+6i)(1-6i) is equal to which of the following?

Expand: (1+6i)(16i)=16i+6i36i2=136i2(1+6i)(1-6i)=1-6i+6i-36i^{2}=1-36i^{2}. Since i2=1i^{2}=-1, this is 1+36=37.1+36=37\textsf{.}

Practice playeasy

What is (2i)2(2i)^2?

(2i)2=4i2=4(1)=4(2i)^2 = 4i^2 = 4(-1) = -4.

Practice playmedium

Given i=1i = \sqrt{-1}, what is 1219\sqrt{121} - \sqrt{-9}?

121=11\sqrt{121} = 11 and 9=3i\sqrt{-9} = 3i. So 1219=113i\sqrt{121} - \sqrt{-9} = 11 - 3i.

Practice playmedium

What is (3+2i)2(3+2i)^{2}?

Expand: (3+2i)2=9+12i+4i2(3+2i)^{2}=9+12i+4i^{2}. Since i2=1i^{2}=-1, this is 9+12i4=5+12i.9+12i-4=5+12i\textsf{.}

Practice playeasy

What is i6i^{6}?

i6=(i2)3=(1)3=1i^{6} = (i^{2})^{3} = (-1)^{3} = -1.

Keep practicing

Turn the complex number system into game time.

The PARCC placement starts with this test's real coverage map and finds the right difficulty.