Missing side from area or perimeter Practice Questions (Grade 4)

Sample questions

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Question 1easy

A rectangle has length $8$ cm and perimeter $40$ cm. What is its width in centimeters?

Perimeter $P = 2(\ell + w)$ , so $40 = 2(8 + w)$ . Then $20 = 8 + w$ , so $w = 12$ cm.

Question 2easy

A rectangle has length $10$ m and perimeter $50$ m. What is its width in meters?

Perimeter $P = 2(\ell + w)$ , so $50 = 2(10 + w)$ . Then $25 = 10 + w$ , so $w = 15$ m.

Question 3easy

A rectangle has length $9$ in and area $72$ in $^2$ . What is its width in inches?

Area $A = \ell w$ , so $72 = 9w$ . Dividing gives $w = 8$ in.

Question 4easy

A square has perimeter $36$ cm. What is the length of one side in centimeters?

A square has four equal sides, so side $s = \dfrac{36}{4} = 9$ cm.

Question 5easy

A square has perimeter $64$ m. What is the length of one side in meters?

A square has four equal sides, so side $s = \dfrac{64}{4} = 16$ m.

Question 6medium

A square has area $64$ cm $^2$ . What is the length of one side in centimeters?

Area $A = s^2$ , so $s = \sqrt{64} = 8$ cm.

Question 7medium

A square has area $144$ ft $^2$ . What is the length of one side in feet?

Area $A = s^2$ , so $s = \sqrt{144} = 12$ ft.

Question 8medium

A rectangle has width $4$ cm and area $56$ cm $^2$ . What is its length in centimeters?

Area $A = \ell w$ , so $56 = 4\ell$ . Dividing gives $\ell = 14$ cm.

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