Grade 9 · Algebra & functions

Scalar times 2×2 matrix (ACT) practice

Scalar times 2×2 matrix (ACT) is a grade 9 math skill aligned to Common Core standard HSN.VM.B.5. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 scalar times 2×2 matrix (act) problems our math games drill.

CCSS HSN.VM.B.510 questions in the bank
Sample questions

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Question 1easy

What is 4[21 03]4\begin{bmatrix} 2 & 1 \ 0 & 3 \end{bmatrix}?

Multiply every entry by 44: [4(2)4(1) 4(0)4(3)]=[84 012]\begin{bmatrix} 4(2) & 4(1) \ 4(0) & 4(3) \end{bmatrix} = \begin{bmatrix} 8 & 4 \ 0 & 12 \end{bmatrix}.

Question 2easy

Which matrix equals 3[21 30]-3\begin{bmatrix} 2 & -1 \ 3 & 0 \end{bmatrix}?

Multiply each entry by 3-3: [3(2)3(1) 3(3)3(0)]=[63 90]\begin{bmatrix} -3(2) & -3(-1) \ -3(3) & -3(0) \end{bmatrix} = \begin{bmatrix} -6 & 3 \ -9 & 0 \end{bmatrix}.

Question 3easy

What is 5[02 11]5\begin{bmatrix} 0 & 2 \ 1 & -1 \end{bmatrix}?

Multiply every entry by 55: [5(0)5(2) 5(1)5(1)]=[010 55]\begin{bmatrix} 5(0) & 5(2) \ 5(1) & 5(-1) \end{bmatrix} = \begin{bmatrix} 0 & 10 \ 5 & -5 \end{bmatrix}.

Question 4easy

Which matrix equals 1[34 25]-1\begin{bmatrix} 3 & 4 \ -2 & 5 \end{bmatrix}?

Multiply each entry by 1-1: [1(3)1(4) 1(2)1(5)]=[34 25]\begin{bmatrix} -1(3) & -1(4) \ -1(-2) & -1(5) \end{bmatrix} = \begin{bmatrix} -3 & -4 \ 2 & -5 \end{bmatrix}.

Question 5easy

What is 2[13 24]2\begin{bmatrix} -1 & 3 \ 2 & 4 \end{bmatrix}?

Multiply every entry by 22: [2(1)2(3) 2(2)2(4)]=[26 48]\begin{bmatrix} 2(-1) & 2(3) \ 2(2) & 2(4) \end{bmatrix} = \begin{bmatrix} -2 & 6 \ 4 & 8 \end{bmatrix}.

Question 6easy

What is 3[21 03]3\begin{bmatrix} -2 & 1 \ 0 & -3 \end{bmatrix}?

Multiply every entry by 33: [3(2)3(1) 3(0)3(3)]=[63 09]\begin{bmatrix} 3(-2) & 3(1) \ 3(0) & 3(-3) \end{bmatrix} = \begin{bmatrix} -6 & 3 \ 0 & -9 \end{bmatrix}.

Question 7medium

Which matrix equals 4[10 32]-4\begin{bmatrix} 1 & 0 \ -3 & 2 \end{bmatrix}?

Multiply each entry by 4-4: [4(1)4(0) 4(3)4(2)]=[40 128]\begin{bmatrix} -4(1) & -4(0) \ -4(-3) & -4(2) \end{bmatrix} = \begin{bmatrix} -4 & 0 \ 12 & -8 \end{bmatrix}.

Question 8medium

Which matrix equals 5[22 13]-5\begin{bmatrix} 2 & -2 \ 1 & 3 \end{bmatrix}?

Multiply each entry by 5-5: [5(2)5(2) 5(1)5(3)]=[1010 515]\begin{bmatrix} -5(2) & -5(-2) \ -5(1) & -5(3) \end{bmatrix} = \begin{bmatrix} -10 & 10 \ -5 & -15 \end{bmatrix}.

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