Scalar times 2×2 matrix (ACT). Game on.

Scalar times 2×2 matrix (ACT) is a grade 9 math skill aligned to Common Core standard HSN.VM.B.5. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 scalar times 2×2 matrix (act) problems our math games drill.

CCSS HSN.VM.B.510 questions in the bank
Kickoff

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Warm-upeasy

What is 4[2103]4\begin{bmatrix} 2 & 1 \\ 0 & 3 \end{bmatrix}?

Multiply every entry by 44: [4(2)4(1)4(0)4(3)]=[84012]\begin{bmatrix} 4(2) & 4(1) \\ 4(0) & 4(3) \end{bmatrix} = \begin{bmatrix} 8 & 4 \\ 0 & 12 \end{bmatrix}.

Mid-gameeasy

Which matrix equals −3[2−130]-3\begin{bmatrix} 2 & -1 \\ 3 & 0 \end{bmatrix}?

Multiply each entry by −3-3: [−3(2)−3(−1)−3(3)−3(0)]=[−63−90]\begin{bmatrix} -3(2) & -3(-1) \\ -3(3) & -3(0) \end{bmatrix} = \begin{bmatrix} -6 & 3 \\ -9 & 0 \end{bmatrix}.

Mid-gameeasy

What is 5[021−1]5\begin{bmatrix} 0 & 2 \\ 1 & -1 \end{bmatrix}?

Multiply every entry by 55: [5(0)5(2)5(1)5(−1)]=[0105−5]\begin{bmatrix} 5(0) & 5(2) \\ 5(1) & 5(-1) \end{bmatrix} = \begin{bmatrix} 0 & 10 \\ 5 & -5 \end{bmatrix}.

Mid-gameeasy

Which matrix equals −1[34−25]-1\begin{bmatrix} 3 & 4 \\ -2 & 5 \end{bmatrix}?

Multiply each entry by −1-1: [−1(3)−1(4)−1(−2)−1(5)]=[−3−42−5]\begin{bmatrix} -1(3) & -1(4) \\ -1(-2) & -1(5) \end{bmatrix} = \begin{bmatrix} -3 & -4 \\ 2 & -5 \end{bmatrix}.

Mid-gameeasy

What is 2[−1324]2\begin{bmatrix} -1 & 3 \\ 2 & 4 \end{bmatrix}?

Multiply every entry by 22: [2(−1)2(3)2(2)2(4)]=[−2648]\begin{bmatrix} 2(-1) & 2(3) \\ 2(2) & 2(4) \end{bmatrix} = \begin{bmatrix} -2 & 6 \\ 4 & 8 \end{bmatrix}.

Mid-gameeasy

What is 3[−210−3]3\begin{bmatrix} -2 & 1 \\ 0 & -3 \end{bmatrix}?

Multiply every entry by 33: [3(−2)3(1)3(0)3(−3)]=[−630−9]\begin{bmatrix} 3(-2) & 3(1) \\ 3(0) & 3(-3) \end{bmatrix} = \begin{bmatrix} -6 & 3 \\ 0 & -9 \end{bmatrix}.

Mid-gamemedium

Which matrix equals −4[10−32]-4\begin{bmatrix} 1 & 0 \\ -3 & 2 \end{bmatrix}?

Multiply each entry by −4-4: [−4(1)−4(0)−4(−3)−4(2)]=[−4012−8]\begin{bmatrix} -4(1) & -4(0) \\ -4(-3) & -4(2) \end{bmatrix} = \begin{bmatrix} -4 & 0 \\ 12 & -8 \end{bmatrix}.

Buzzer beatermedium

Which matrix equals −5[2−213]-5\begin{bmatrix} 2 & -2 \\ 1 & 3 \end{bmatrix}?

Multiply each entry by −5-5: [−5(2)−5(−2)−5(1)−5(3)]=[−1010−5−15]\begin{bmatrix} -5(2) & -5(-2) \\ -5(1) & -5(3) \end{bmatrix} = \begin{bmatrix} -10 & 10 \\ -5 & -15 \end{bmatrix}.

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