Simplifying rational expressions (ACT). Game on.

Simplifying rational expressions (ACT) is a grade 9 math skill aligned to Common Core standard HSA.APR.D.6. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 simplifying rational expressions (act) problems our math games drill.

CCSS HSA.APR.D.610 questions in the bank
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Warm-upeasy

Which expression is equivalent to x25x+6x24\dfrac{x^{2}-5x+6}{x^{2}-4} when x2x \neq 2 and x2?x \neq -2\textsf{?}

Factor: (x2)(x3)(x2)(x+2)=x3x+2\dfrac{(x-2)(x-3)}{(x-2)(x+2)}=\dfrac{x-3}{x+2} for x±2.x \neq \pm 2\textsf{.}

Mid-gameeasy

Which expression is equivalent to x21x2+2x+1\dfrac{x^{2}-1}{x^{2}+2x+1} when x1?x \neq -1\textsf{?}

Factor: (x1)(x+1)(x+1)(x+1)=x1x+1\dfrac{(x-1)(x+1)}{(x+1)(x+1)}=\dfrac{x-1}{x+1} for x1.x \neq -1\textsf{.}

Mid-gamemedium

Which expression is equivalent to x2+5x+6x2+3x+2\dfrac{x^{2}+5x+6}{x^{2}+3x+2} when x1x \neq -1 and x2?x \neq -2\textsf{?}

Factor: (x+2)(x+3)(x+1)(x+2)=x+3x+1\dfrac{(x+2)(x+3)}{(x+1)(x+2)}=\dfrac{x+3}{x+1} for x1x \neq -1 and x2.x \neq -2\textsf{.}

Mid-gamemedium

Which expression is equivalent to x29x+20x28x+15\dfrac{x^{2}-9x+20}{x^{2}-8x+15} when x3x \neq 3 and x5?x \neq 5\textsf{?}

Factor: (x4)(x5)(x3)(x5)=x4x3\dfrac{(x-4)(x-5)}{(x-3)(x-5)}=\dfrac{x-4}{x-3} for x3x \neq 3 and x5.x \neq 5\textsf{.}

Mid-gamemedium

Which expression is equivalent to x38x24\dfrac{x^{3}-8}{x^{2}-4} when x2x \neq 2 and x2?x \neq -2\textsf{?}

Factor: (x2)(x2+2x+4)(x2)(x+2)=x2+2x+4x+2\dfrac{(x-2)(x^{2}+2x+4)}{(x-2)(x+2)}=\dfrac{x^{2}+2x+4}{x+2} for x±2.x \neq \pm 2\textsf{.}

Mid-gamemedium

Which expression is equivalent to x31x21\dfrac{x^{3}-1}{x^{2}-1} when x1x \neq 1 and x1?x \neq -1\textsf{?}

Factor: (x1)(x2+x+1)(x1)(x+1)=x2+x+1x+1\dfrac{(x-1)(x^{2}+x+1)}{(x-1)(x+1)}=\dfrac{x^{2}+x+1}{x+1} for x±1.x \neq \pm 1\textsf{.}

Mid-gamemedium

Which expression is equivalent to 2x32x2x22x\dfrac{2x^{3}-2x}{2x^{2}-2x} when x0x \neq 0 and x1?x \neq 1\textsf{?}

Factor: 2x(x1)(x+1)2x(x1)=x+1\dfrac{2x(x-1)(x+1)}{2x(x-1)}=x+1 for x0x \neq 0 and x1.x \neq 1\textsf{.}

Buzzer beaterhard

Which expression is equivalent to x3+2x2x2x2+x2\dfrac{x^{3}+2x^{2}-x-2}{x^{2}+x-2} when x2x \neq -2 and x1?x \neq 1\textsf{?}

Factor by grouping: (x21)(x+2)(x+2)(x1)=(x1)(x+1)(x+2)(x+2)(x1)=x+1\dfrac{(x^{2}-1)(x+2)}{(x+2)(x-1)}=\dfrac{(x-1)(x+1)(x+2)}{(x+2)(x-1)}=x+1 for x2x \neq -2 and x1.x \neq 1\textsf{.}

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