Galvanic Cells Quiz
The question sheet
Reveal any answer as you study-
Galvanic cells produce electrical energy from what kind of reaction?
- Nonspontaneous decomposition
- Precipitation reactions
- Endothermic dissolution
- Spontaneous oxidation-reduction
Reveal answer
Answer: Spontaneous oxidation-reduction
Source evidence
PDF page 865: Galvanic cells, also known as voltaic cells, are electrochemical cells in which spontaneous oxidation-reduction reactions produce electrical energy. In writing the equations, it is often convenient to separate the oxidation-reduction reactions into half-reactions to facilitate balancing the overall equation and to emphasize the actual chemical transformations. Consider what happens when a clean piece of copper metal is placed in a solution of silver nitrate (Figure 16.3). As soon as the copper metal is added, silver metal begins to form and copper ions pass into the solution. The blue color of the solution on the far right indicates the presence of copper ions. The reaction may be split into its two half-reactions. Half-reactions separate the oxidation from the reduction, so each can be considered individually.
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Galvanic cells are also known by what other name?
- Concentration cells
- Fuel cells
- Electrolytic cells
- Voltaic cells
Reveal answer
Answer: Voltaic cells
Source evidence
PDF page 865: Galvanic cells, also known as voltaic cells, are electrochemical cells in which spontaneous oxidation-reduction reactions produce electrical energy. In writing the equations, it is often convenient to separate the oxidation-reduction reactions into half-reactions to facilitate balancing the overall equation and to emphasize the actual chemical transformations. Consider what happens when a clean piece of copper metal is placed in a solution of silver nitrate (Figure 16.3). As soon as the copper metal is added, silver metal begins to form and copper ions pass into the solution. The blue color of the solution on the far right indicates the presence of copper ions. The reaction may be split into its two half-reactions. Half-reactions separate the oxidation from the reduction, so each can be considered individually.
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Why must the silver reduction half-reaction be doubled in the copper/silver reaction?
- To equal electrons lost and gained
- To remove spectator ions
- To balance the mass of silver
- To increase the cell potential
Reveal answer
Answer: To equal electrons lost and gained
Source evidence
PDF page 865: The equation for the reduction half-reaction had to be doubled so the number electrons “gained” in the reduction halfreaction equaled the number of electrons “lost” in the oxidation half-reaction.
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In the copper/silver galvanic cell, the copper electrode is which electrode?
- Cathode
- Salt bridge
- Anode
- Inert electrode
Reveal answer
Answer: Anode
Source evidence
PDF page 865: Galvanic or voltaic cells involve spontaneous electrochemical reactions in which the half-reactions are separated (Figure 16.4) so that current can flow through an external wire. The beaker on the left side of the figure is called a half-cell, and contains a 1 M solution of copper(II) nitrate [Cu(NO3)2] with a piece of copper metal partially submerged in the solution. The copper metal is an electrode. The copper is undergoing oxidation; therefore, the copper electrode is the anode. The anode is connected to a voltmeter with a wire and the other terminal of the voltmeter is connected to a silver electrode by a wire. The silver is undergoing reduction; therefore, the silver electrode is the cathode. The half-cell on the right side of the figure consists of the silver electrode in a 1 M solution of silver nitrate (AgNO3). At this point, no current flows—that is, no significant movement of electrons through the wire occurs because the circuit is open. The circuit is closed using a salt bridge, which transmits the current with moving ions. The salt bridge consists of a concentrated, nonreactive, electrolyte solution such as the sodium nitrate (NaNO3) solution used in this example. As electrons flow from left to right through the electrode and wire, nitrate ions (anions) pass through the porous plug on the left into the copper(II) nitrate solution. This keeps the beaker on the left electrically neutral by neutralizing the charge on the copper(II) ions that are produced in the solution as the copper metal is oxidized. At the same time, the nitrate ions are moving to the left, sodium ions (cations) move to the right, through
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The silver electrode, where reduction occurs, is called the:
- Cathode
- Salt bridge
- Anode
- Voltmeter
Reveal answer
Answer: Cathode
Source evidence
PDF page 865: Galvanic or voltaic cells involve spontaneous electrochemical reactions in which the half-reactions are separated (Figure 16.4) so that current can flow through an external wire. The beaker on the left side of the figure is called a half-cell, and contains a 1 M solution of copper(II) nitrate [Cu(NO3)2] with a piece of copper metal partially submerged in the solution. The copper metal is an electrode. The copper is undergoing oxidation; therefore, the copper electrode is the anode. The anode is connected to a voltmeter with a wire and the other terminal of the voltmeter is connected to a silver electrode by a wire. The silver is undergoing reduction; therefore, the silver electrode is the cathode. The half-cell on the right side of the figure consists of the silver electrode in a 1 M solution of silver nitrate (AgNO3). At this point, no current flows—that is, no significant movement of electrons through the wire occurs because the circuit is open. The circuit is closed using a salt bridge, which transmits the current with moving ions. The salt bridge consists of a concentrated, nonreactive, electrolyte solution such as the sodium nitrate (NaNO3) solution used in this example. As electrons flow from left to right through the electrode and wire, nitrate ions (anions) pass through the porous plug on the left into the copper(II) nitrate solution. This keeps the beaker on the left electrically neutral by neutralizing the charge on the copper(II) ions that are produced in the solution as the copper metal is oxidized. At the same time, the nitrate ions are moving to the left, sodium ions (cations) move to the right, through
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What closes the circuit in a galvanic cell by transmitting current with moving ions?
- The salt bridge
- The porous plug alone
- The external wire
- The voltmeter
Reveal answer
Answer: The salt bridge
Source evidence
PDF page 865: Galvanic or voltaic cells involve spontaneous electrochemical reactions in which the half-reactions are separated (Figure 16.4) so that current can flow through an external wire. The beaker on the left side of the figure is called a half-cell, and contains a 1 M solution of copper(II) nitrate [Cu(NO3)2] with a piece of copper metal partially submerged in the solution. The copper metal is an electrode. The copper is undergoing oxidation; therefore, the copper electrode is the anode. The anode is connected to a voltmeter with a wire and the other terminal of the voltmeter is connected to a silver electrode by a wire. The silver is undergoing reduction; therefore, the silver electrode is the cathode. The half-cell on the right side of the figure consists of the silver electrode in a 1 M solution of silver nitrate (AgNO3). At this point, no current flows—that is, no significant movement of electrons through the wire occurs because the circuit is open. The circuit is closed using a salt bridge, which transmits the current with moving ions. The salt bridge consists of a concentrated, nonreactive, electrolyte solution such as the sodium nitrate (NaNO3) solution used in this example. As electrons flow from left to right through the electrode and wire, nitrate ions (anions) pass through the porous plug on the left into the copper(II) nitrate solution. This keeps the beaker on the left electrically neutral by neutralizing the charge on the copper(II) ions that are produced in the solution as the copper metal is oxidized. At the same time, the nitrate ions are moving to the left, sodium ions (cations) move to the right, through
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What does the salt bridge consist of in the example cell?
- A gold electrode
- A copper wire
- A concentrated NaNO3 solution
- Pure distilled water
Reveal answer
Answer: A concentrated NaNO3 solution
Source evidence
PDF page 865: Galvanic or voltaic cells involve spontaneous electrochemical reactions in which the half-reactions are separated (Figure 16.4) so that current can flow through an external wire. The beaker on the left side of the figure is called a half-cell, and contains a 1 M solution of copper(II) nitrate [Cu(NO3)2] with a piece of copper metal partially submerged in the solution. The copper metal is an electrode. The copper is undergoing oxidation; therefore, the copper electrode is the anode. The anode is connected to a voltmeter with a wire and the other terminal of the voltmeter is connected to a silver electrode by a wire. The silver is undergoing reduction; therefore, the silver electrode is the cathode. The half-cell on the right side of the figure consists of the silver electrode in a 1 M solution of silver nitrate (AgNO3). At this point, no current flows—that is, no significant movement of electrons through the wire occurs because the circuit is open. The circuit is closed using a salt bridge, which transmits the current with moving ions. The salt bridge consists of a concentrated, nonreactive, electrolyte solution such as the sodium nitrate (NaNO3) solution used in this example. As electrons flow from left to right through the electrode and wire, nitrate ions (anions) pass through the porous plug on the left into the copper(II) nitrate solution. This keeps the beaker on the left electrically neutral by neutralizing the charge on the copper(II) ions that are produced in the solution as the copper metal is oxidized. At the same time, the nitrate ions are moving to the left, sodium ions (cations) move to the right, through
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What cell potential does the voltmeter read the instant the circuit is completed?
- +0.46 V
- 0.00 V
- -0.46 V
- +1.10 V
Reveal answer
Answer: +0.46 V
Source evidence
PDF page 866: the porous plug, and into the silver nitrate solution on the right. These added cations “replace” the silver ions that are removed from the solution as they were reduced to silver metal, keeping the beaker on the right electrically neutral. Without the salt bridge, the compartments would not remain electrically neutral and no significant current would flow. However, if the two compartments are in direct contact, a salt bridge is not necessary. The instant the circuit is completed, the voltmeter reads +0.46 V, this is called the cell potential. The cell potential is created when the two dissimilar metals are connected, and is a measure of the energy per unit charge available from the oxidation-reduction reaction. The volt is the derived SI unit for electrical potential J
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The volt is the derived SI unit for what quantity?
- Electrical potential
- Current
- Electric charge
- Resistance
Reveal answer
Answer: Electrical potential
Source evidence
PDF page 866: the porous plug, and into the silver nitrate solution on the right. These added cations “replace” the silver ions that are removed from the solution as they were reduced to silver metal, keeping the beaker on the right electrically neutral. Without the salt bridge, the compartments would not remain electrically neutral and no significant current would flow. However, if the two compartments are in direct contact, a salt bridge is not necessary. The instant the circuit is completed, the voltmeter reads +0.46 V, this is called the cell potential. The cell potential is created when the two dissimilar metals are connected, and is a measure of the energy per unit charge available from the oxidation-reduction reaction. The volt is the derived SI unit for electrical potential J
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In the standard galvanic cell, electrons flow in which direction?
- Randomly in both directions
- Through the salt bridge
- Cathode to anode
- Anode to cathode
Reveal answer
Answer: Anode to cathode
Source evidence
PDF page 866: • Electrons flow from the anode to the cathode: left to right in the standard galvanic cell in the figure.
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A positive cell potential in this arrangement indicates what about the reaction?
- It is at equilibrium
- It is nonspontaneous
- It is spontaneous
- It absorbs heat
Reveal answer
Answer: It is spontaneous
Source evidence
PDF page 866: When the electrochemical cell is constructed in this fashion, a positive cell potential indicates a spontaneous reaction and that the electrons are flowing from the left to the right. There is a lot going on in Figure 16.4, so it is useful to summarize things for this system:
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In cell notation, what does a double line ‖ denote?
- An electrode surface
- A phase boundary
- A spectator ion
- The salt bridge
Reveal answer
Answer: The salt bridge
Source evidence
PDF page 867: for current to flow. There are many possible galvanic cells, so a shorthand notation is usually used to describe them. The cell notation (sometimes called a cell diagram) provides information about the various species involved in the reaction. This notation also works for other types of cells. A vertical line, │, denotes a phase boundary and a double line, ‖, the salt bridge. Information about the anode is written to the left, followed by the anode solution, then the salt bridge (when present), then the cathode solution, and, finally, information about the cathode to the right. The cell notation for the galvanic cell in Figure 16.4 is then 2+ + Cu(s) │ Cu (aq, 1 M) ║ Ag (aq, 1 M) │ Ag(s) Note that spectator ions are not included and that the simplest form of each half-reaction was used. When known, the initial concentrations of the various ions are usually included. One of the simplest cells is the Daniell cell. It is possible to construct this battery by placing a copper electrode at the bottom of a jar and covering the metal with a copper sulfate solution. A zinc sulfate solution is floated on top of the copper sulfate solution; then a zinc electrode is placed in the zinc sulfate solution. Connecting the copper electrode to the zinc electrode allows an electric current to flow. This is an example of a cell without a salt bridge, and ions may flow across the interface between the two solutions. Some oxidation-reduction reactions involve species that are poor conductors of electricity, and so an electrode is used that does not participate in the reactions. Frequently, the electrode is platinum, gold, or graphite, all of which are inert to many chemical reactions. One such system is shown in Figure 16.5. Magnesium undergoes oxidation at the anode on the left in the figure and hydrogen ions undergo reduction at the cathode on the right. The reaction may be summarized as 2+ − oxidation: Mg(s) ⟶ Mg (aq) + 2e + − reduction: 2H (aq) + 2e ⟶ H (g) 2 2+ + overall: Mg(s) + 2H (aq) ⟶ Mg (aq) + H (g) 2 The cell used an inert platinum wire for the cathode, so the cell notation is 2+ + Mg(s) │ Mg (aq) ║ H (aq) │ H (g) │ Pt(s) 2 The magnesium electrode is an active electrode because it participates in the oxidation-reduction reaction. Inert electrodes, like the platinum electrode in Figure 16.5, do not participate in the oxidation-reduction reaction and are present so that current can flow through the cell. Platinum or gold generally make good inert electrodes because they are chemically unreactive.
Chemistry: Atoms First
Chemistry: Atoms First by OpenStax, used under CC BY 4.0. Changes made by Stratacademy.
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