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Occurrence, Preparation, and Properties of Transition Metals and Their Compounds Quiz

12 questions chemistry Grades 9-12

The question sheet

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  1. In which groups are the d-block transition elements located?

    • Groups 15-18
    • Groups 3-11
    • Groups 12-14
    • Groups 1-2
    Reveal answer

    Answer: Groups 3-11

    Source evidence

    PDF page 1064: Figure 19.2, the d-block elements in groups 3–11 are transition elements. The f-block elements, also called inner

  2. Why are group 12 elements technically NOT transition elements?

    • They are nonmetals
    • They form no cations
    • They lack any d orbitals
    • Their d orbitals are already filled
    Reveal answer

    Answer: Their d orbitals are already filled

    Source evidence

    PDF page 1064: transition metals (the lanthanides and actinides), also meet this criterion because the d orbital is partially occupied before the f orbitals. The d orbitals fill with the copper family (group 11); for this reason, the next family (group

    PDF page 1064: 12) are technically not transition elements. However, the group 12 elements do display some of the same chemical

  3. Which elements make up the first transition series?

    • Sc through Cu
    • Y through Ag
    • Ce through Lu
    • La through Au
    Reveal answer

    Answer: Sc through Cu

    Source evidence

    PDF page 1064: The d-block elements are divided into the first transition series (the elements Sc through Cu), the second transition

  4. For transition metal ions, which electrons are removed first?

    • d electrons
    • s electrons
    • f electrons
    • p electrons
    Reveal answer

    Answer: s electrons

    Source evidence

    PDF page 1065: Review how to write electron configurations, covered in the chapter on electronic structure and periodic properties of elements. Recall that for the transition and inner transition metals, it is necessary to remove the s electrons before the d or f electrons. Then, for each ion, give the electron configuration:

    PDF page 1065: For the examples that are transition metals, determine to which series they belong. Solution For ions, the s-valence electrons are lost prior to the d or f electrons.

  5. How many rare earth elements are there?

    • 17
    • 14
    • 15
    • 11
    Reveal answer

    Answer: 17

    Source evidence

    PDF page 1065: than silver (4.5 × 10 % versus 0.79 × 10 % by mass). There are 17 rare earth elements, consisting of the 15 lanthanoids plus scandium and yttrium. They are called rare because they were once difficult to extract economically, so it was rare to have a pure sample; due to similar chemical properties, it is difficult to separate any one lanthanide from the others. However, newer separation methods, such as ion exchange resins similar to those found in home water softeners, make the separation of these elements easier and more economical.

  6. Which physical property is typical of transition elements?

    • Liquid at room temperature
    • Poor heat conductors
    • Hard high-melting solids
    • Soft low-melting solids
    Reveal answer

    Answer: Hard high-melting solids

    Source evidence

    PDF page 1066: The transition elements have many properties in common with other metals. They are almost all hard, high-melting solids that conduct heat and electricity well. They readily form alloys and lose electrons to form stable cations. In addition, transition metals form a wide variety of stable coordination compounds, in which the central metal atom or ion acts as a Lewis acid and accepts one or more pairs of electrons. Many different molecules and ions can donate lone pairs to the metal center, serving as Lewis bases. In this chapter, we shall focus primarily on the chemical behavior of the elements of the first transition series.

  7. In coordination compounds, the central metal ion acts as a:

    • Proton donor
    • Lewis base
    • Reducing agent
    • Lewis acid
    Reveal answer

    Answer: Lewis acid

    Source evidence

    PDF page 1066: The transition elements have many properties in common with other metals. They are almost all hard, high-melting solids that conduct heat and electricity well. They readily form alloys and lose electrons to form stable cations. In addition, transition metals form a wide variety of stable coordination compounds, in which the central metal atom or ion acts as a Lewis acid and accepts one or more pairs of electrons. Many different molecules and ions can donate lone pairs to the metal center, serving as Lewis bases. In this chapter, we shall focus primarily on the chemical behavior of the elements of the first transition series.

  8. What aqueous cation charge do all lanthanides form?

    • 2+
    • 1+
    • 4+
    • 3+
    Reveal answer

    Answer: 3+

    Source evidence

    PDF page 1066: Transition metals demonstrate a wide range of chemical behaviors. As can be seen from their reduction potentials (see Appendix H), some transition metals are strong reducing agents, whereas others have very low reactivity. For example, the lanthanides all form stable 3+ aqueous cations. The driving force for such oxidations is similar to that of

  9. On heating, oxygen reacts with all transition elements EXCEPT:

    • Chromium, manganese, iron
    • Palladium, platinum, silver, gold
    • Iron, cobalt, nickel, copper
    • Scandium, titanium, vanadium
    Reveal answer

    Answer: Palladium, platinum, silver, gold

    Source evidence

    PDF page 1067: water. However, ions in the period just below these (Mo , Ru , and Ir ) are unstable and react readily with oxygen from the air. The majority of simple, water-stable ions formed by the heavier d-block elements are oxyanions such as − 2− and ReO . MoO 4 4 Ruthenium, osmium, rhodium, iridium, palladium, and platinum are the platinum metals. With difficulty, they form simple cations that are stable in water, and, unlike the earlier elements in the second and third transition series, they do not form stable oxyanions. Both the d- and f-block elements react with nonmetals to form binary compounds; heating is often required. These elements react with halogens to form a variety of halides ranging in oxidation state from 1+ to 6+. On heating, oxygen reacts with all of the transition elements except palladium, platinum, silver, and gold. The oxides of these latter metals can be formed using other reactants, but they decompose upon heating. The f-block elements, the elements of group 3, and the elements of the first transition series except copper react with aqueous solutions of acids, forming hydrogen gas and solutions of the corresponding salts. Transition metals can form compounds with a wide range of oxidation states. Some of the observed oxidation states of the elements of the first transition series are shown in Figure 19.4. As we move from left to right across the first transition series, we see that the number of common oxidation states increases at first to a maximum towards the middle of the table, then decreases. The values in the table are typical values; there are other known values, and it is possible to synthesize new additions. For example, in 2014, researchers were successful in synthesizing a new oxidation state of iridium (9+).

  10. For Sc through Mn, the highest oxidation state corresponds to loss of all electrons in which orbitals?

    • Only p orbitals
    • Only f orbitals
    • Only d orbitals
    • Both s and d valence orbitals
    Reveal answer

    Answer: Both s and d valence orbitals

    Source evidence

    PDF page 1067: For the elements scandium through manganese (the first half of the first transition series), the highest oxidation state corresponds to the loss of all of the electrons in both the s and d orbitals of their valence shells. The titanium(IV) ion, for example, is formed when the titanium atom loses its two 3d and two 4s electrons. These highest oxidation states are the most stable forms of scandium, titanium, and vanadium. However, it is not possible to continue to remove all of the valence electrons from metals as we continue through the series. Iron is known to form oxidation states from 2+ to 6+, with iron(II) and iron(III) being the most common. Most of the elements of the first transition series form ions with a charge of 2+ or 3+ that are stable in water, although those of the early members of the series can be readily oxidized by air. The elements of the second and third transition series generally are more stable in higher oxidation states than are the elements of the first series. In general, the atomic radius increases down a group, which leads to the ions of the second and third series being larger than are those in the first series. Removing electrons from orbitals that are located farther from the nucleus is easier than removing electrons close to the nucleus. For example, molybdenum and tungsten, members of group 6, are limited mostly to an oxidation state of 6+ in aqueous solution. Chromium,

  11. Which are the most common oxidation states of iron?

    • Iron(V) and iron(VI)
    • Iron(II) and iron(III)
    • Iron(I) and iron(II)
    • Iron(IV) and iron(V)
    Reveal answer

    Answer: Iron(II) and iron(III)

    Source evidence

    PDF page 1067: For the elements scandium through manganese (the first half of the first transition series), the highest oxidation state corresponds to the loss of all of the electrons in both the s and d orbitals of their valence shells. The titanium(IV) ion, for example, is formed when the titanium atom loses its two 3d and two 4s electrons. These highest oxidation states are the most stable forms of scandium, titanium, and vanadium. However, it is not possible to continue to remove all of the valence electrons from metals as we continue through the series. Iron is known to form oxidation states from 2+ to 6+, with iron(II) and iron(III) being the most common. Most of the elements of the first transition series form ions with a charge of 2+ or 3+ that are stable in water, although those of the early members of the series can be readily oxidized by air. The elements of the second and third transition series generally are more stable in higher oxidation states than are the elements of the first series. In general, the atomic radius increases down a group, which leads to the ions of the second and third series being larger than are those in the first series. Removing electrons from orbitals that are located farther from the nucleus is easier than removing electrons close to the nucleus. For example, molybdenum and tungsten, members of group 6, are limited mostly to an oxidation state of 6+ in aqueous solution. Chromium,

  12. Which is the strongest oxidizing agent in acidic solution?

    • Chromium(III) ion
    • Permanganate ion
    • Titanium dioxide
    • Dichromate ion
    Reveal answer

    Answer: Permanganate ion

    Source evidence

    PDF page 1068: 2 2 A larger reduction potential means that it is easier to reduce the reactant. Permanganate, with the largest reduction potential, is the strongest oxidizer under these conditions. Dichromate is next, followed by titanium dioxide as the weakest oxidizing agent (the hardest to reduce) of this set. Check Your Learning Predict what reaction (if any) will occur between HCl and Co(s), and between HBr and Pt(s). You will need to use the standard reduction potentials from Appendix L.

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