SOL Algebra II Statistics and Probability. Practice it free.

Students interpret data and use probability and statistical models to make inferences. This Algebra II reporting domain maps to 4 practice skills and 8 representative questions from the playable bank.

Algebra II4 mapped skills
What the test measures

Statistics and Probability skills

  1. conditional probability

  2. normal distributions

  3. inference and regression

  4. two-way tables and correlations

Standards basis

Virginia Mathematics Standards of Learning — Virginia

How the SOL reports it

Virginia SOL math is a state-specific assessment program built around the Virginia Mathematics Standards of Learning rather than a shared national test framework. It is aligned to Virginia grade-level and course standards, which are generally CCSS-like in organization but are published as Virginia-specific standards.

Blueprint & weighting

SOL uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

From a table, 5 are members who renew AND are premium and 12 total are premium members. Find the conditional probability of renewing given premium (simplified fraction).

P(AB)=P(A and B)P(B)=512=512P(A\mid B) = \dfrac{P(A \text{ and } B)}{P(B)} = \dfrac{5}{12} = \dfrac{5}{12}.

Practice playeasy

A normal distribution has mean 100100 and standard deviation 1515. What value is 1 standard deviation above the mean?

100+1×15=115100 + 1\times15 = 115.

Practice playeasy

A librarian checked 4040 books selected at random from a collection of 800800 books. She found that 1414 of the books in the sample were fiction. Based on the sample, which of the following is the best estimate of the number of fiction books in the collection?

The sample proportion is 1440=720\dfrac{14}{40} = \dfrac{7}{20}. The best estimate for the collection is 720×800=280\dfrac{7}{20} \times 800 = 280 books.

Practice playeasy

In a class of 2020 students, 1212 students bring lunch from home, and 44 of those students also bring a reusable water bottle. If a student who brings lunch from home is selected at random, what is the probability that the student also brings a reusable water bottle?

Restrict to the 1212 students who bring lunch from home. 44 of them also bring a bottle, so P(bottlelunch from home)=412=13.P(\text{bottle} \mid \text{lunch from home}) = \dfrac{4}{12} = \dfrac{1}{3}\textsf{.}

Practice playeasy

From a table, 10 are customers who buy AND saw the ad and 25 total are customers who saw the ad. Find the conditional probability of buying given saw the ad (simplified fraction).

P(AB)=P(A and B)P(B)=1025=25P(A\mid B) = \dfrac{P(A \text{ and } B)}{P(B)} = \dfrac{10}{25} = \dfrac{2}{5}.

Practice playeasy

A normal distribution has mean 5050 and standard deviation 55. What value is 2 standard deviation below the mean?

502×5=4050 - 2\times5 = 40.

Practice playeasy

A ball is tossed upward from a platform. The equation h=4.9t2+14t+21h = -4.9t^2 + 14t + 21 represents this situation, where hh is the height of the ball above the ground, in meters, tt seconds after it is tossed. According to the equation, what is the height, in meters, of the platform from which the ball was tossed?

At the moment of release, t=0t = 0. Substituting gives h=4.9(0)2+14(0)+21=21h = -4.9(0)^2 + 14(0) + 21 = 21 meters.

Practice playeasy

The letters of the word BANANA are placed in a bag. Two letters are selected one at a time without replacement. What is the probability of drawing an A and then an N?

The word BANANA has 66 letters with 33 A's and 22 N's. P(A first)=36P(\text{A first}) = \dfrac{3}{6} and P(N secondA first)=25P(\text{N second} \mid \text{A first}) = \dfrac{2}{5}, so P(A then N)=36×25=15.P(\text{A then N}) = \dfrac{3}{6} \times \dfrac{2}{5} = \dfrac{1}{5}\textsf{.}

Keep practicing

Turn statistics and probability into game time.

The SOL placement starts with this test's real coverage map and finds the right difficulty.