SOL Grades 6-8 Computation and Estimation. Practice it free.

$2^{6} = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 = 64\textsf{.}$

The base $4$ appears $2$ times as a factor, so $4 \times 4 = 4^{2}$.

Multiply first: $8 \cdot 7 = 56$. Then $3 + 56 - 2 = 57$.

$\,2^2 = 2 \cdot 2 = 4$.

$5.70 \times 5 = 28.5$.

Result: $-6$.

Multiply across: $\dfrac{3 \times 1}{5 \times 6} = \dfrac{3}{30} = \dfrac{1}{10}$.

Any base to the first power equals itself: $3^{1} = 3\textsf{.}$