STAAR Grade 7 Geometry and Measurement. Practice it free.

Use geometric attributes and measurement concepts to solve problems. This Grade 7 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 739 mapped skills
What the test measures

Geometry and Measurement skills

  1. solve problems with angles, scale drawings, and geometric figures

  2. determine area, circumference, and surface area

  3. use geometric transformations and coordinate geometry

  4. apply measurement relationships in context

  5. TEKS mathematical process standards applied to grade 7 content

Standards basis

Texas Essential Knowledge and Skills (TEKS) for Mathematics — Texas

How the STAAR reports it

STAAR math is a Texas state assessment built on the Texas Essential Knowledge and Skills (TEKS), not a Common Core framework. Texas publishes explicit STAAR reporting categories by grade/course, with item reporting aligned to TEKS content strands and student expectations.

Blueprint & weighting

TEA’s publicly visible STAAR Mathematics Resources page does not publish item weights in the page content reviewed here. The category structure is explicit, but no percentage blueprint was visible in the sourced materials.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius 11 and height 55. Using π=3\pi = 3, what is its volume?

V=πr2h=3×1×5=15V = \pi r^2 h = 3 \times 1 \times 5 = 15.

Practice playhard

A rectangular prism has volume 160160 cubic inches and height 55 inches. The length is twice the width. What is the length, in inches?

V=whV = \ell w h and =2w\ell = 2w, so 160=(2w)(w)(5)=10w2160 = (2w)(w)(5) = 10w^2. Then w2=16w^2 = 16, so w=4w = 4 and =8 in.\ell = 8\text{ in}\textsf{.}

Practice playmedium

A factory seals soup in closed cylindrical cans with radius 33 centimeters and height 55 centimeters. What is the total exterior surface area, in square centimeters, of one closed can?

A closed cylinder has two circular bases and a lateral surface: SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh. With r=3r = 3 and h=5h = 5, SA=2π(9)+2π(3)(5)=18π+30π=48πSA = 2\pi(9) + 2\pi(3)(5) = 18\pi + 30\pi = 48\pi square centimeters.

Practice playeasy

Find the volume of a sphere with radius 33. Use π=3\pi = 3.

V=43πr3=43×3×27=108V = \dfrac{4}{3} \pi r^{3} = \dfrac{4}{3} \times 3 \times 27 = 108.

Practice playmedium

Two sides of a triangle measure 1616 and 9.9\textsf{.} Which inequality gives the possible lengths, x,x\textsf{,} of the third side?

The triangle inequality requires 169<x<16+9.|16 - 9| < x < 16 + 9\textsf{.} Simplifying gives 7<x<25.7 < x < 25\textsf{.}

Practice playeasy

Similar triangles GHIGHI and JKLJKL have perimeters 1616 and 48.48\textsf{.} Side GHGH corresponds to side JK,JK\textsf{,} and GH=5.GH = 5\textsf{.} What is the length of JK?JK\textsf{?}

The scale factor from GHI\triangle GHI to JKL\triangle JKL is 4816=3.\dfrac{48}{16} = 3\textsf{.} Corresponding sides scale by 3,3\textsf{,} so JK=53=15.JK = 5 \cdot 3 = 15\textsf{.}

Practice playeasy

Two angles are complementary. One measures 60°60°. What is the other?

9060=30°90 - 60 = 30°.

Practice playeasy

A circle has a radius of 1111 centimeters. What is the circumference, in centimeters, of the circle?

The circumference of a circle is C=2πrC = 2\pi r. Substitute r=11r = 11: C=2π(11)=22π.C = 2\pi(11) = 22\pi\textsf{.}

Keep practicing

Turn geometry and measurement into game time.

The STAAR placement starts with this test's real coverage map and finds the right difficulty.