ISASP High School Number and Quantity. Practice it free.

The number of campers must divide both $28$ and $42$. The common factors greater than $1$ are $2$, $7$, and $14$. Only $7$ appears among the choices: $28 \div 7 = 4$ tokens and $42 \div 7 = 6$ coupons per camper.

Expand: $(5-3i)(-2+i)=-10+5i+6i-3i^{2}$. Since $i^{2}=-1$, this is $-10+11i+3=-7+11i\textsf{.}$

$(4i)^2 = 16i^2 = 16(-1) = -16$.

$\sqrt{4} = 2$ and $\sqrt{-16} = 4i$. So $\sqrt{4} + \sqrt{-16} = 2 + 4i$.

Substitute $t = 5$: $f(5) = 3e^{10} + 10$. Since $e^{10} \approx 22{,}026$, $f(5) \approx 3(22{,}026) + 10 = 66{,}088 \approx 7 \times 10^{4}$.

Maximize the numerator with $m = 6$ and $n = 4$, and minimize the denominator with $p = 5$: $\dfrac{6 + 4}{5} = 2$.

The cafe needs the least common multiple of $8$ and $14$ so the muffin and bagel totals match. Since the GCF of $8$ and $14$ is $2\textsf{,}$ divide their product by the GCF: $\dfrac{8 \times 14}{2}=56\textsf{.}$ So the least matching total is $56\textsf{.}$

$720{,}000 = 7.2 \times 10^5$, so $n = 5$.