KAP Grade 7 Statistics and Probability. Practice it free.

Uses random sampling, comparative inference, and probability to draw conclusions from data. This Grade 7 reporting domain maps to 8 practice skills and 8 representative questions from the playable bank.

Grade 78 mapped skills
What the test measures

Statistics and Probability skills

  1. Use random sampling to draw inferences about a population

  2. Draw informal comparative inferences about two populations

  3. Investigate chance processes and develop, use, and evaluate probability models

  4. Estimate probabilities and interpret them as long-run relative frequencies

  5. Find probabilities of compound events using organized lists, tables, tree diagrams, and simulations

Standards basis

Kansas College and Career Ready Standards for Mathematics (CCRS-M), closely aligned to Common Core State Standards for Mathematics (CCSS-M) — Kansas

How the KAP reports it

Kansas Assessment Program appears to be a state assessment program rather than a vendor framework like Smarter Balanced or PARCC. The public KAP site did not expose a math blueprint or reporting-category document in the pages I could access, so the safest official mapping is to the state's adopted mathematics standards structure that the assessment is built to.

Blueprint & weighting

KAP uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

For two independent events, the probability of a head then a 4: P(A)=12P(A)=\tfrac{1}{2}, P(B)=16P(B)=\tfrac{1}{6}. Find P(A and B)P(A \text{ and } B) as a simplified fraction.

Multiply: P(A and B)=12×16=112P(A \text{ and } B) = \tfrac{1}{2} \times \tfrac{1}{6} = \tfrac{1}{12}.

Practice playmedium

A whole number from 11 through 2525 is chosen at random. What is the probability that the number is a multiple of 44?

The multiples of 44 from 11 to 2525 are 4,8,12,16,20,4, 8, 12, 16, 20, and 2424, so P=625P = \dfrac{6}{25}.

Practice playeasy

A spinner has 88 equal sections: 22 are green and 66 are yellow. What is the probability the spinner lands on green?

P(green)=28=14P(\text{green}) = \dfrac{2}{8} = \dfrac{1}{4}.

Practice playeasy

The whole numbers 11 through 5050 were each written on separate cards. Those 5050 cards were placed in a hat. One card will be randomly drawn from this hat. What is the probability that the card will show a number divisible by 55?

Multiples of 55 from 11 to 5050 are 5,10,15,20,25,30,35,40,45,505, 10, 15, 20, 25, 30, 35, 40, 45, 50, giving 1010 favorable outcomes: P=1050=15P = \tfrac{10}{50} = \tfrac{1}{5}.

Practice playeasy

What is the probability of rolling an even number on a die? Give a simplified fraction.

P=favorabletotal=36=12P = \dfrac{\text{favorable}}{\text{total}} = \dfrac{3}{6} = \dfrac{1}{2}.

Practice playeasy

A spinner with 33 equal sections is spun, and a standard six-sided die is rolled. How many outcomes are in the sample space?

A tree diagram starts with 33 branches for the spinner. Each of those splits into 66 die branches, so the sample space has 3×6=18.3 \times 6 = 18\textsf{.}

Practice playeasy

A random sample of 20 contained 5 successes. What is the sample proportion (as a simplified fraction)?

Proportion =520=14= \dfrac{5}{20} = \dfrac{1}{4}.

Practice playeasy

A game spinner has 88 equal sections, exactly 22 of which are blue. A fair coin is then flipped. What is the probability of landing on blue on the spinner and getting tails on the coin?

P(blue)=28=14P(\text{blue}) = \dfrac{2}{8} = \dfrac{1}{4} and P(tails)=12P(\text{tails}) = \dfrac{1}{2}. So P(both)=14×12=18P(\text{both}) = \dfrac{1}{4} \times \dfrac{1}{2} = \dfrac{1}{8}.

Keep practicing

Turn statistics and probability into game time.

The KAP placement starts with this test's real coverage map and finds the right difficulty.