KAP Grade 7 Geometry. Practice it free.

Draws, constructs, and analyzes geometric figures and relationships among them. This Grade 7 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 79 mapped skills
What the test measures

Geometry skills

  1. Solve problems involving angle measure, area, surface area, and volume

  2. Draw geometric shapes with given conditions

  3. Describe the two-dimensional figures that result from slicing three-dimensional figures

  4. Use facts about supplementary, complementary, vertical, and adjacent angles

  5. Investigate congruence and similarity in geometric figures

Standards basis

Kansas College and Career Ready Standards for Mathematics (CCRS-M), closely aligned to Common Core State Standards for Mathematics (CCSS-M) — Kansas

How the KAP reports it

Kansas Assessment Program appears to be a state assessment program rather than a vendor framework like Smarter Balanced or PARCC. The public KAP site did not expose a math blueprint or reporting-category document in the pages I could access, so the safest official mapping is to the state's adopted mathematics standards structure that the assessment is built to.

Blueprint & weighting

KAP uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

Two lines cross. One angle formed is 75°75°. What is the vertical angle?

Vertical angles are equal, so the angle is 75°75°.

Practice playeasy

Similar triangles RSTRST and UVWUVW have perimeters 2828 and 42.42\textsf{.} Side RSRS corresponds to side UV,UV\textsf{,} and RS=10.RS = 10\textsf{.} What is the length of UV?UV\textsf{?}

The scale factor from RST\triangle RST to UVW\triangle UVW is 4228=32.\dfrac{42}{28} = \dfrac{3}{2}\textsf{.} So UV=1032=15.UV = 10 \cdot \dfrac{3}{2} = 15\textsf{.}

Practice playeasy

A triangle has side lengths 77 and 3.3\textsf{.} Which inequality represents the possible lengths, x,x\textsf{,} of the third side?

The triangle inequality requires 73<x<7+3.|7 - 3| < x < 7 + 3\textsf{.} Simplifying gives 4<x<10.4 < x < 10\textsf{.}

Practice playeasy

A cylinder has radius 22 and height 33. Using π=3\pi = 3, what is its volume?

V=πr2h=3×4×3=36V = \pi r^2 h = 3 \times 4 \times 3 = 36.

Practice playeasy

A circle has a diameter of 1616 inches. What is the area, in square inches, of the circle?

The radius is half the diameter: r=162=8r = \dfrac{16}{2} = 8. The area is A=πr2=π(8)2=64π.A = \pi r^{2} = \pi(8)^{2} = 64\pi\textsf{.}

Practice playeasy

A circle has radius 22. Using π=3\pi = 3, what is its circumference?

C=2πr=2×3×2=12C = 2\pi r = 2 \times 3 \times 2 = 12.

Practice playhard

A rectangular prism has volume 160160 cubic inches and height 55 inches. The length is twice the width. What is the length, in inches?

V=whV = \ell w h and =2w\ell = 2w, so 160=(2w)(w)(5)=10w2160 = (2w)(w)(5) = 10w^2. Then w2=16w^2 = 16, so w=4w = 4 and =8 in.\ell = 8\text{ in}\textsf{.}

Practice playmedium

A museum display is shaped like a closed square pyramid with a 66-centimeter-by-66-centimeter base. Each triangular face has slant height 55 centimeters. What is the total exterior surface area, in square centimeters, of the display?

The base area is 62=366^2 = 36. The four congruent triangular faces each have area 12(6)(5)=15\dfrac{1}{2}(6)(5) = 15, for a total of 4×15=604 \times 15 = 60. The surface area is 36+60=9636 + 60 = 96 square centimeters.

Keep practicing

Turn geometry into game time.

The KAP placement starts with this test's real coverage map and finds the right difficulty.